numpy.array_equiv(arr1, arr2) : This logical function that checks if two arrays have the same elements and shape consistent.
Shape consistent means either they are having the same shape, or one input array can be broadcasted to create the same shape as the other one.
Parameters :
arr1 : [array_like]Input array, we need to test. arr2 : [array_like]Input array, we need to test.
Return :
True, if both arrays are equivalent; otherwise False
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Code : Explaining Working
# Python program explaining # array_equiv() function import numpy as np   # input arr1 = np.arange(4) arr2 = [7, 4, 6, 7] print ("arr1 : ", arr1) print ("arr2 : ", arr2)   print ("\nResult : ", np.array_equiv(arr1, arr2))   arr1 = np.arange(4) arr2 = np.arange(4) print ("\n\narr1 : ", arr1) print ("arr2 : ", arr2)   print ("\nResult : ", np.array_equiv(arr1, arr2))   arr1 = np.arange(4) arr2 = np.arange(5) print ("\n\narr1 : ", arr1) print ("arr2 : ", arr2)   print ("\nResult : ", np.array_equiv(arr1, arr2))     a = np.array_equiv([1, 2], [[1, 2, 1, 2], [1, 2, 1, 2]])   b = np.array_equiv([1, 2], [[1, 2], [1, 2]])   print ("\n\na : ", a) print ("\nb : ", b) |
Output :
arr1 : [0 1 2 3] arr2 : [7, 4, 6, 7] Result : False arr1 : [0 1 2 3] arr2 : [0 1 2 3] Result : True arr1 : [0 1 2 3] arr2 : [0 1 2 3 4] Result : False a : False b : True
References :
https://docs.scipy.org/doc/numpy-1.13.0/reference/generated/numpy.array_equiv.html#numpy.array_equiv
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