Given an array arr and a number K, find the new array formed by performing XOR of the corresponding element from the given array with the given number K.
Examples:
Input: arr[] = { 2, 4, 1, 3, 5 }, K = 5
Output: 7 1 4 6 0
Explanation:
2 XOR 5 = 7
4 XOR 5 = 1
1 XOR 5 = 4
3 XOR 5 = 6
5 XOR 5 = 0
Input: arr[] = { 4, 75, 45, 42 }, K = 2
Output: 6 73 47 40
Approach:
- Traverse the given array.
- Then calculate the XOR of each element with K.
- Then store it as the element at that index in the output array.
- Print the updated array.
Below is the implementation of the above approach.
CPP
// C++ program to find XOR of every element// of an array with a given number K#include <bits/stdc++.h>using namespace std;// Function to construct new arrayvoid constructXORArray(int A[], int n, int K){ int B[n]; // Traverse the array and // compute XOR with K for (int i = 0; i < n; i++) B[i] = A[i] ^ K; // Print new array for (int i = 0; i < n; i++) cout << B[i] << " "; cout << endl;}// Driver codeint main(){ int A[] = { 2, 4, 1, 3, 5 }; int K = 5; int n = sizeof(A) / sizeof(A[0]); constructXORArray(A, n, K); int B[] = { 4, 75, 45, 42 }; K = 2; n = sizeof(B) / sizeof(B[0]); constructXORArray(B, n, K); return 0;} |
Java
// Java program to find XOR of every element// of an array with a given number Kimport java.util.*;class GFG{// Function to construct new arraystatic void constructXORArray(int A[], int n, int K){ int[] B = new int[n]; // Traverse the array and // compute XOR with K for (int i = 0; i < n; i++) B[i] = A[i] ^ K; // Print new array for (int i = 0; i < n; i++) System.out.print( B[i] +" "); System.out.println();}// Driver code public static void main(String args[]) { int A[] = { 2, 4, 1, 3, 5 }; int K = 5; int n = A.length; constructXORArray(A, n, K); int B[] = { 4, 75, 45, 42 }; K = 2; n = B.length; constructXORArray(B, n, K);}}// This code is contributed by shivanisinghss2110 |
Python3
# Python program to find XOR of every element# of an array with a given number K# Function to construct new arraydef constructXORArray(A, n, K): B = [0]*n; # Traverse the array and # compute XOR with K for i in range(n): B[i] = A[i] ^ K; # Print new array for i in range(n): print(B[i], end=" "); print();# Driver codeif __name__ == '__main__': A = [ 2, 4, 1, 3, 5 ]; K = 5; n = len(A); constructXORArray(A, n, K); B = [ 4, 75, 45, 42 ]; K = 2; n = len(B); constructXORArray(B, n, K);# This code contributed by sapnasingh4991 |
C#
// C# program to find XOR of every element// of an array with a given number Kusing System;class GFG{ // Function to construct new arraystatic void constructXORArray(int []A, int n, int K){ int[] B = new int[n]; // Traverse the array and // compute XOR with K for (int i = 0; i < n; i++) B[i] = A[i] ^ K; // Print new array for (int i = 0; i < n; i++) Console.Write( B[i] +" "); Console.WriteLine();} // Driver code public static void Main(String []args) { int []A = { 2, 4, 1, 3, 5 }; int K = 5; int n = A.Length; constructXORArray(A, n, K); int []B = { 4, 75, 45, 42 }; K = 2; n = B.Length; constructXORArray(B, n, K);}}// This code is contributed by Rajput-Ji |
Javascript
<script> // Javascript program to find XOR of every element // of an array with a given number K // Function to construct new array function constructXORArray(A, n, K) { let B = new Array(n); // Traverse the array and // compute XOR with K for (let i = 0; i < n; i++) B[i] = A[i] ^ K; // Print new array for (let i = 0; i < n; i++) document.write(B[i] + " "); document.write("</br>") } let A = [ 2, 4, 1, 3, 5 ]; let K = 5; let n = A.length; constructXORArray(A, n, K); let B = [ 4, 75, 45, 42 ]; K = 2; n = B.length; constructXORArray(B, n, K); // This code is contributed by divyeshrabadiya07.</script> |
Output:
7 1 4 6 0 6 73 47 40
Time Complexity: O(n)
Auxiliary Space: O(n)
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