Permutation.next_lex() : next_lex() is a sympy Python library function that returns the next permutation in lexicographical order and if in case the self is the last permutation in lexicographical order it returns None.
Syntax : sympy.combinatorics.permutations.Permutation.next_lex()
Return : next permutation in lexicographical order
Code #1 : next_lex() Example
# Python code explaining # SymPy.Permutation.next_lex() # importing SymPy libraries from sympy.combinatorics.partitions import Partition from sympy.combinatorics.permutations import Permutation # Using from sympy.combinatorics.permutations.Permutation.next_lex() method # creating Permutation a = Permutation([[2, 0], [3, 1]]) b = Permutation([1, 3, 5, 4, 2, 0]) print ("Permutation a - next_lex form : ", a.next_lex()) print ("Permutation b - next_lex form : ", b.next_lex()) |
Output :
Permutation a – next_lex form : (0 2 1 3)
Permutation b – next_lex form : (5)(0 1 4 3 2)
Code #2 : next_lex() Example – 2D Permutation
# Python code explaining # SymPy.Permutation.next_lex() # importing SymPy libraries from sympy.combinatorics.partitions import Partition from sympy.combinatorics.permutations import Permutation # Using from sympy.combinatorics.permutations.Permutation.next_lex() method # creating Permutation a = Permutation([[2, 4, 0], [3, 1, 2], [1, 5, 6]]) print ("Permutation a - next_lex form : ", a.next_lex()) |
Output :
Permutation a – next_lex form : (6)(0 3 5)(1 2 4)
