Permutation.next_lex() : next_lex() is a sympy Python library function that returns the next permutation in lexicographical order and if in case the self is the last permutation in lexicographical order it returns None.
Syntax : sympy.combinatorics.permutations.Permutation.next_lex()
Return : next permutation in lexicographical order
Code #1 : next_lex() Example
| # Python code explaining # SymPy.Permutation.next_lex()  # importing SymPy libraries fromsympy.combinatorics.partitions importPartition fromsympy.combinatorics.permutations importPermutation  # Using from sympy.combinatorics.permutations.Permutation.next_lex() method   # creating Permutation a =Permutation([[2, 0], [3, 1]])  b =Permutation([1, 3, 5, 4, 2, 0])   print("Permutation a - next_lex form : ", a.next_lex()) print("Permutation b - next_lex form : ", b.next_lex())  | 
Output :
Permutation a – next_lex form : (0 2 1 3)
Permutation b – next_lex form : (5)(0 1 4 3 2)
Code #2 : next_lex() Example – 2D Permutation
| # Python code explaining # SymPy.Permutation.next_lex()  # importing SymPy libraries fromsympy.combinatorics.partitions importPartition fromsympy.combinatorics.permutations importPermutation  # Using from sympy.combinatorics.permutations.Permutation.next_lex() method   # creating Permutation a =Permutation([[2, 4, 0],                   [3, 1, 2],                  [1, 5, 6]])   print("Permutation a - next_lex form : ", a.next_lex())  | 
Output :
Permutation a – next_lex form : (6)(0 3 5)(1 2 4)

 
                                    







