Given a positive integer N, the task is to check whether the given number N is Sunny Number or not.
A number N is a sunny number if N + 1 is a perfect square.
Examples:
Input: N = 8
Output: Yes
Explanation:
Since 9 is a perfect square. therefore 8 is a sunny number.Input: N = 11
Output: No
Explanation:
Since 12 is not a perfect square. therefore 8 is not a sunny number.
Approach: The idea is to check whether (N + 1) is a perfect square or not.
Below is the implementation of the above approach:
C++
// C++ program for the above approach#include "bits/stdc++.h"using namespace std;// Function check whether x is a// perfect square or notbool isPerfectSquare(long double x){ // Find floating point value of // square root of x. long double sr = sqrt(x); // If square root is an integer return((sr - floor(sr)) == 0);}// Function to check Sunny Numbervoid checkSunnyNumber(int N){ // Check if (N + 1) is a perfect // square or not if (isPerfectSquare(N + 1)) { cout << "Yes\n"; } // If (N+1) is not a perfect square else { cout << "No\n"; }}// Driver Codeint main(){ // Given Number int N = 8; // Function call checkSunnyNumber(N); return 0;} |
Java
// Java program for the above approachimport java.util.*;class GFG { // Function check whether x is a// perfect square or notstatic boolean isPerfectSquare(double x){ // Find floating point value of // square root of x. double sr = Math.sqrt(x); // If square root is an integer return((sr - Math.floor(sr)) == 0);}// Function to check Sunny Numberstatic void checkSunnyNumber(int N){ // Check if (N + 1) is a perfect // square or not if (isPerfectSquare(N + 1)) { System.out.println("Yes"); } // If (N+1) is not a perfect square else { System.out.println("No"); }}// Driver code public static void main(String[] args){ // Given Number int N = 8; // Function call checkSunnyNumber(N);}}// This code is contributed by offbeat |
Python3
# Python3 program for the above approachfrom math import *# Function check whether x is a# perfect square or notdef isPerfectSquare(x): # Find floating point value of # square root of x. sr = sqrt(x) # If square root is an integer return((sr - floor(sr)) == 0)# Function to check Sunny Numberdef checkSunnyNumber(N): # Check if (N + 1) is a perfect # square or not if (isPerfectSquare(N + 1)): print("Yes") # If (N+1) is not a perfect square else: print("No")# Driver Codeif __name__ == '__main__': # Given Number N = 8 # Function call checkSunnyNumber(N)# This code is contributed by Bhupendra_Singh |
C#
// C# program for the above approachusing System;class GFG { // Function check whether x is// a perfect square or notstatic bool isPerfectSquare(double x){ // Find floating point value of // square root of x. double sr = Math.Sqrt(x); // If square root is an integer return((sr - Math.Floor(sr)) == 0);}// Function to check sunny numberstatic void checkSunnyNumber(int N){ // Check if (N + 1) is a perfect // square or not if (isPerfectSquare(N + 1)) { Console.WriteLine("Yes"); } // If (N+1) is not a perfect square else { Console.WriteLine("No"); }}// Driver code public static void Main(String[] args){ // Given Number int N = 8; // Function call checkSunnyNumber(N);}}// This code is contributed by Rohit_ranjan |
Javascript
<script>// Javascript program for the above approach// Function check whether x is a// perfect square or notfunction isPerfectSquare(x){ // Find floating point value of // square root of x. var sr = Math.sqrt(x); // If square root is an integer return((sr - Math.floor(sr)) == 0);}// Function to check Sunny Numberfunction checkSunnyNumber(N){ // Check if (N + 1) is a perfect // square or not if (isPerfectSquare(N + 1)) { document.write( "Yes"); } // If (N+1) is not a perfect square else { document.write( "No"); }}// Driver Code// Given Numbervar N = 8;// Function callcheckSunnyNumber(N);// This code is contributed by noob2000.</script> |
Output:
Yes
Time Complexity: O(1)
Auxiliary Space: O(1)
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