The java.lang.StrictMath.sqrt() is an inbuilt method of StrictMath class in Java which is used to obtain the exact rounded positive square root of a specified double value. Syntax:
public static double sqrt(double num)
Parameters: The function accepts a single parameter num of double type, whose square root is to be returned by the function. Return Values: This method returns the positive square root of num. it also gives rise to doubt special cases:
- The function returns NaN if the argument is NaN or less than zero
- The function returns positive infinity when the argument is positive infinite.
- The function returns zero with the same sign as the argument if the argument is zero
- The result is the double value nearest to the mathematical square root of the argument value.
Examples:
Input: num = 25 Output: 5.0 Input: -729 Output: NaN
Below programs illustrate the use of java.lang.StrictMath.sqrt() method: Program 1:Â
Java
// Java Program to illustrate// java.lang.StrictMath.sqrt() functionimport java.lang.*;Â
public class Geeks {Â
    public static void main(String[] args)    {Â
        double num1 = 289, num2 = -729;        double num3 = 0.0, num4 = 547.87;Â
        // It returns the positive square root        double sqrt_Value = StrictMath.sqrt(num1);        System.out.println("square root = " + sqrt_Value);Â
        sqrt_Value = StrictMath.sqrt(num2);        System.out.println("square root = " + sqrt_Value);Â
        sqrt_Value = StrictMath.sqrt(num3);        System.out.println("square root = " + sqrt_Value);Â
        sqrt_Value = StrictMath.sqrt(num4);        System.out.println("square root = " + sqrt_Value);    }} |
Output:
square root = 17.0 square root = NaN square root = 0.0 square root = 23.406622994357814
Program 2:Â
Java
// Java Program to illustrate// java.lang.StrictMath.sqrt() functionimport java.lang.*;Â
public class Geeks {Â
    public static void main(String[] args)    {Â
        double num1 = 1160, num2 = -97;        double num3 = -0.0, num4 = 144;        double num5 = -72.18;Â
        // It returns the positive square root        double sqrt_Value = StrictMath.sqrt(num1);        System.out.println("square root = " + sqrt_Value);Â
        sqrt_Value = StrictMath.sqrt(num2);        System.out.println("square root = " + sqrt_Value);Â
        sqrt_Value = StrictMath.sqrt(num3);        System.out.println("square root = " + sqrt_Value);Â
        sqrt_Value = StrictMath.sqrt(num4);        System.out.println("square root = " + sqrt_Value);Â
        sqrt_Value = StrictMath.sqrt(num5);        System.out.println("square root = " + sqrt_Value);    }} |
Output:
square root = 34.058772731852805 square root = NaN square root = -0.0 square root = 12.0 square root = NaN
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