The java.lang.StrictMath.floor() is the inbuilt method which returns the largest double value, less than or equal to the given argument and is equal to the integer value.
- The result is the same as the argument when the given argument is equal to the integer.
- The result is the same as the argument when the given argument is NaN, infinity, positive zero or negative zero.
Syntax :
public static double floor(double num)
Parameters: This method accepts one parameter num which is of double type .
Return Value : The method returns the largest value which, closest to positive infinity, less than or equal to the argument and equal to an integer.
Examples :
Input: num = 9.6 Output: 9.0 Input: num = -7.8 Output: -8.0
Below programs illustrate the java.lang.StrictMath.floor() method:
Program 1:
java
// Java program to illustrate the//java.lang.StrictMath.floor()import java.lang.*;public class Geeks {public static void main(String[] args) { double num1 = 7.8, num2 = 1.4 ; double fValue = StrictMath.floor(num1); System.out.println("The floor value of "+ num1+" = " + fValue); fValue = StrictMath.floor(num2); System.out.println("The floor value of "+ num2+" = " + fValue);}} |
Output:
The floor value of 7.8 = 7.0 The floor value of 1.4 = 1.0
Program2:
java
// Java program to illustrate the//java.lang.StrictMath.floor()import java.lang.*;public class Geeks {public static void main(String[] args) { double num1 = -7.8, num2 = -1.4 ,num3 = 0.1 ; double fValue = StrictMath.floor(num1); System.out.println("The floor value of "+ num1+" = " + fValue); fValue = StrictMath.floor(num2); System.out.println("The floor value of "+ num2+" = " + fValue); fValue = StrictMath.floor(num3); System.out.println("The floor value of "+ num3+" = " + fValue);}} |
Output:
The floor value of -7.8 = -8.0 The floor value of -1.4 = -2.0 The floor value of 0.1 = 0.0
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