Python timedelta() function is present under datetime library which is generally used for calculating differences in dates and also can be used for date manipulations in Python. It is one of the easiest ways to perform date manipulations.
Syntax : datetime.timedelta(days=0, seconds=0, microseconds=0, milliseconds=0, minutes=0, hours=0, weeks=0)
Returns : Date
Code #1:
Python3
# Timedelta function demonstrationfrom datetime import datetime, timedelta# Using current timeini_time_for_now = datetime.now()# printing initial_dateprint ("initial_date", str(ini_time_for_now))# Calculating future dates# for two yearsfuture_date_after_2yrs = ini_time_for_now + \ timedelta(days = 730)future_date_after_2days = ini_time_for_now + \ timedelta(days = 2)# printing calculated future_datesprint('future_date_after_2yrs:', str(future_date_after_2yrs))print('future_date_after_2days:', str(future_date_after_2days)) |
Output:
initial_date 2019-02-27 12:41:45.018389 future_date_after_2yrs: 2021-02-26 12:41:45.018389 future_date_after_2days: 2019-03-01 12:41:45.018389
Code #2:
Python3
# Timedelta function demonstrationfrom datetime import datetime, timedelta# Using current timeini_time_for_now = datetime.now()# printing initial_dateprint ('initial_date:', str(ini_time_for_now))# Calculating past dates# for two yearspast_date_before_2yrs = ini_time_for_now - \ timedelta(days = 730)# for two hourspast_date_before_2hours = ini_time_for_now - \ timedelta(hours = 2)# printing calculated past_datesprint('past_date_before_2yrs:', str(past_date_before_2yrs))print('past_date_before_2hours:', str(past_date_before_2hours)) |
Output:
initial_date 2019-02-27 12:41:46.104662 past_date_before_2yrs: 2017-02-27 12:41:46.104662 past_date_after_2days: 2019-02-27 10:41:46.104662
Code #3:
Python3
# Timedelta function demonstrationfrom datetime import datetime, timedelta# Using current timeini_time_for_now = datetime.now()# printing initial_dateprint ("initial_date", str(ini_time_for_now))# Some another datetimenew_final_time = ini_time_for_now + \ timedelta(days = 2)# printing new final_dateprint ("new_final_time", str(new_final_time))# printing calculated past_datesprint('Time difference:', str(new_final_time - \ ini_time_for_now)) |
Output:
initial_date 2019-02-27 12:41:47.386595 new_final_time 2019-03-01 12:41:47.386595 Time difference: 2 days, 0:00:00
Subtracting a timedelta object from a date or datetime object:
Approach:
Create a timedelta object with the desired time difference.
Subtract the timedelta object from a date or datetime object using the – operator.
Python3
import datetimetoday = datetime.date.today()three_days_ago = today - datetime.timedelta(days=3)print("Today:", today)print("Three days ago:", three_days_ago) |
Output
Today: 2023-03-24 Three days ago: 2023-03-21
Time complexity: O(1)
Auxiliary Space: O(1)
