Given a Matrix, convert it into dictionary with keys as row number and value as nested list.
Input : test_list = [[5, 6, 7], [8, 3, 2]] Output : {1: [5, 6, 7], 2: [8, 3, 2]} Explanation : Matrix rows are paired with row number in order. Input : test_list = [[5, 6, 7]] Output : {1: [5, 6, 7]} Explanation : Matrix rows are paired with row number in order.
Method #1 : Using dictionary comprehension + range()
The combination of above functions can be used to solve this problem. In this, we perform the task of iteration using dictionary comprehension and range() can be used to perform numbering of rows.
Python3
# Python3 code to demonstrate working of # Convert Matrix to dictionary # Using dictionary comprehension + range()# initializing listtest_list = [[5, 6, 7], [8, 3, 2], [8, 2, 1]] # printing original listprint("The original list is : " + str(test_list))# using dictionary comprehension for iterationres = {idx + 1 : test_list[idx] for idx in range(len(test_list))}# printing result print("The constructed dictionary : " + str(res)) |
The original list is : [[5, 6, 7], [8, 3, 2], [8, 2, 1]]
The constructed dictionary : {1: [5, 6, 7], 2: [8, 3, 2], 3: [8, 2, 1]}
Time Complexity: O(n) where n is the number of elements in the list test_list.
Auxiliary Space: O(n), where n is the number of elements in the list test_list.
Method #2 : Using dictionary comprehension + enumerate()
The combination of above functions can be used to solve this problem. In this, dictionary comprehension help in construction of dictionary and enumerate() helps in iteration like range() in above method.
Python3
# Python3 code to demonstrate working of # Convert Matrix to dictionary # Using dictionary comprehension + enumerate()# initializing listtest_list = [[5, 6, 7], [8, 3, 2], [8, 2, 1]] # printing original listprint("The original list is : " + str(test_list))# enumerate used to perform assigning row numberres = {idx: val for idx, val in enumerate(test_list, start = 1)}# printing result print("The constructed dictionary : " + str(res)) |
The original list is : [[5, 6, 7], [8, 3, 2], [8, 2, 1]]
The constructed dictionary : {1: [5, 6, 7], 2: [8, 3, 2], 3: [8, 2, 1]}
