Given the current time in the form of HH::MM, where H represents the hours and M, represents the minutes in a 24-hour time format. The task is to calculate the time remaining for the day to complete as HH::MM.
Examples:
Input: HH::MM = 00::01 Output: 23::01 Input: HH::MM = 23::55 Output: 00::05
Approach:
- Since the total minutes in a 24 hour complete day is 24 * 60 = 1440 minutes
- Calculate the time completed in minutes
- Calculate the time remaining in the form of minutes as total minutes – time completed
- Convert the time remaining in the form of HH::MM
Below is the implementation of the above approach:
CPP
#include <bits/stdc++.h>using namespace std;// Function to find the remaining timevoid remainingTime(int h, int m){ int totalMin, hoursRemaining, minRemaining; // Formula for total remaining minutes // = 1440 - 60h - m totalMin = 1440 - 60 * h - m; // Remaining hours hoursRemaining = totalMin / 60; // Remaining minutes minRemaining = totalMin % 60; cout << hoursRemaining << "::" << minRemaining << endl;}// Driver codeint main(){ // Current time int h = 0, m = 1; // Get the remaining time remainingTime(h, m); return 0;} |
Java
class GFG{// Function to find the remaining timestatic void remainingTime(int h, int m){ int totalMin, hoursRemaining, minRemaining; // Formula for total remaining minutes // = 1440 - 60h - m totalMin = 1440 - 60 * h - m; // Remaining hours hoursRemaining = totalMin / 60; // Remaining minutes minRemaining = totalMin % 60; System.out.print(hoursRemaining+ "::" + minRemaining +"\n");}// Driver codepublic static void main(String[] args){ // Current time int h = 0, m = 1; // Get the remaining time remainingTime(h, m);}}// This code is contributed by Rajput-Ji |
Python
# Function to find the remaining timedef remainingTime(h, m): # Formula for total remaining minutes # = 1440 - 60h - m totalMin = 1440 - 60 * h - m # Remaining hours hoursRemaining = totalMin // 60 # Remaining minutes minRemaining = totalMin % 60 print(hoursRemaining,"::",minRemaining)# Driver code# Current timeh = 0m = 1# Get the remaining timeremainingTime(h, m)# This code is contributed by mohit kumar 29 |
C#
// C# program to Number of pairs of lines// having integer intersection pointsusing System;class GFG{ // Function to find the remaining time static void remainingTime(int h, int m) { int totalMin, hoursRemaining, minRemaining; // Formula for total remaining minutes // = 1440 - 60h - m totalMin = 1440 - 60 * h - m; // Remaining hours hoursRemaining = totalMin / 60; // Remaining minutes minRemaining = totalMin % 60; Console.WriteLine(hoursRemaining+ "::" + minRemaining); } // Driver code public static void Main() { // Current time int h = 0, m = 1; // Get the remaining time remainingTime(h, m); }}// This code is contributed by AnkitRai01 |
Javascript
<script>// Javascript program to Number of pairs of lines// having integer intersection points // Function to find the remaining time function remainingTime(h, m) { var totalMin, hoursRemaining, minRemaining; // Formula for total remaining minutes // = 1440 - 60h - m totalMin = 1440 - 60 * h - m; // Remaining hours hoursRemaining = totalMin / 60; // Remaining minutes minRemaining = totalMin % 60; document.write(Math.trunc(hoursRemaining)+ "::" + minRemaining); } // Driver code // Current time var h = 0, m = 1; // Get the remaining time remainingTime(h, m); </script> |
Output:
23::59
Time Complexity: O(1)
Auxiliary Space: O(1)
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