Given two sparse matrices (Sparse Matrix and its representations | Set 1 (Using Arrays and Linked Lists)), perform operations such as add, multiply or transpose of the matrices in their sparse form itself. The result should consist of three sparse matrices, one obtained by adding the two input matrices, one by multiplying the two matrices and one obtained by transpose of the first matrix.Â
Example: Note that other entries of matrices will be zero as matrices are sparse.
Input : Matrix 1: (4x4) Row Column Value 1 2 10 1 4 12 3 3 5 4 1 15 4 2 12 Matrix 2: (4X4) Row Column Value 1 3 8 2 4 23 3 3 9 4 1 20 4 2 25 Output : Result of Addition: (4x4) Row Column Value 1 2 10 1 3 8 1 4 12 2 4 23 3 3 14 4 1 35 4 2 37 Result of Multiplication: (4x4) Row Column Value 1 1 240 1 2 300 1 4 230 3 3 45 4 3 120 4 4 276 Result of transpose on the first matrix: (4x4) Row Column Value 1 4 15 2 1 10 2 4 12 3 3 5 4 1 12
The sparse matrix used anywhere in the program is sorted according to its row values. Two elements with the same row values are further sorted according to their column values.Â
Now to Add the matrices, we simply traverse through both matrices element by element and insert the smaller element (one with smaller row and col value) into the resultant matrix. If we come across an element with the same row and column value, we simply add their values and insert the added data into the resultant matrix.Â
To Transpose a matrix, we can simply change every column value to the row value and vice-versa, however, in this case, the resultant matrix won’t be sorted as we require. Hence, we initially determine the number of elements less than the current element’s column being inserted in order to get the exact index of the resultant matrix where the current element should be placed. This is done by maintaining an array index[] whose ith value indicates the number of elements in the matrix less than the column i.Â
To Multiply the matrices, we first calculate transpose of the second matrix to simplify our comparisons and maintain the sorted order. So, the resultant matrix is obtained by traversing through the entire length of both matrices and summing the appropriate multiplied values.Â
Any row value equal to x in the first matrix and row value equal to y in the second matrix (transposed one) will contribute towards result[x][y]. This is obtained by multiplying all such elements having col value in both matrices and adding only those with the row as x in first matrix and row as y in the second transposed matrix to get the result[x][y].Â
For example: Consider 2 matrices:
Row Col Val Row Col Val 1 2 10 1 1 2 1 3 12 1 2 5 2 1 1 2 2 1 2 3 2 3 1 8
The resulting matrix after multiplication will be obtained as follows:
Transpose of second matrix: Row Col Val Row Col Val 1 2 10 1 1 2 1 3 12 1 3 8 2 1 1 2 1 5 2 3 2 2 2 1 Summation of multiplied values: result[1][1] = A[1][3]*B[1][3] = 12*8 = 96 result[1][2] = A[1][2]*B[2][2] = 10*1 = 10 result[2][1] = A[2][1]*B[1][1] + A[2][3]*B[1][3] = 2*1 + 2*8 = 18 result[2][2] = A[2][1]*B[2][1] = 1*5 = 5 Any other element cannot be obtained by any combination of row in Matrix A and Row in Matrix B. Hence the final resultant matrix will be: Row Col Val 1 1 96 1 2 10 2 1 18 2 2 5
Following is the implementation of above approach:Â
C++
// C++ code to perform add, multiply // and transpose on sparse matrices#include <iostream>using namespace std;Â
class sparse_matrix{Â
    // Maximum number of elements in matrix    const static int MAX = 100;Â
    // Double-pointer initialized by     // the constructor to store     // the triple-represented form    int **data;Â
    // dimensions of matrix    int row, col;Â
    // total number of elements in matrix    int len;Â
public:Â Â Â Â sparse_matrix(int r, int c)Â Â Â Â {Â
        // initialize row        row = r;Â
        // initialize col        col = c;Â
        // initialize length to 0        len = 0;Â
        //Array of Pointer to make a matrix        data = new int *[MAX];Â
        // Array representation        // of sparse matrix        //[,0] represents row        //[,1] represents col        //[,2] represents value        for (int i = 0; i < MAX; i++)            data[i] = new int[3];    }Â
    // insert elements into sparse matrix    void insert(int r, int c, int val)    {Â
        // invalid entry        if (r > row || c > col)        {            cout << "Wrong entry";        }        else        {Â
            // insert row value            data[len][0] = r;Â
            // insert col value            data[len][1] = c;Â
            // insert element's value            data[len][2] = val;Â
            // increment number of data in matrix            len++;        }    }Â
    void add(sparse_matrix b)    {Â
        // if matrices don't have same dimensions        if (row != b.row || col != b.col)        {            cout << "Matrices can't be added";        }Â
        else        {            int apos = 0, bpos = 0;            sparse_matrix result(row, col);Â
            while (apos < len && bpos < b.len)            {Â
                // if b's row and col is smaller                if (data[apos][0] > b.data[bpos][0] ||                   (data[apos][0] == b.data[bpos][0] &&                    data[apos][1] > b.data[bpos][1]))Â
                {Â
                    // insert smaller value into result                    result.insert(b.data[bpos][0],                                  b.data[bpos][1],                                  b.data[bpos][2]);Â
                    bpos++;                }Â
                // if a's row and col is smaller                else if (data[apos][0] < b.data[bpos][0] ||                        (data[apos][0] == b.data[bpos][0] &&                         data[apos][1] < b.data[bpos][1]))Â
                {Â
                    // insert smaller value into result                    result.insert(data[apos][0],                                  data[apos][1],                                  data[apos][2]);Â
                    apos++;                }Â
                else                {Â
                    // add the values as row and col is same                    int addedval = data[apos][2] +                                  b.data[bpos][2];Â
                    if (addedval != 0)                        result.insert(data[apos][0],                                      data[apos][1],                                      addedval);                    // then insert                    apos++;                    bpos++;                }            }Â
            // insert remaining elements            while (apos < len)                result.insert(data[apos][0],                              data[apos][1],                              data[apos++][2]);Â
            while (bpos < b.len)                result.insert(b.data[bpos][0],                              b.data[bpos][1],                              b.data[bpos++][2]);Â
            // print result            result.print();        }    }Â
    sparse_matrix transpose()    {Â
        // new matrix with inversed row X col        sparse_matrix result(col, row);Â
        // same number of elements        result.len = len;Â
        // to count number of elements in each column        int *count = new int[col + 1];Â
        // initialize all to 0        for (int i = 1; i <= col; i++)            count[i] = 0;Â
        for (int i = 0; i < len; i++)            count[data[i][1]]++;Â
        int *index = new int[col + 1];Â
        // to count number of elements having         // col smaller than particular iÂ
        // as there is no col with value < 0        index[0] = 0;Â
        // initialize rest of the indices        for (int i = 1; i <= col; i++)Â
            index[i] = index[i - 1] + count[i - 1];Â
        for (int i = 0; i < len; i++)        {Â
            // insert a data at rpos and             // increment its value            int rpos = index[data[i][1]]++;Â
            // transpose row=col            result.data[rpos][0] = data[i][1];Â
            // transpose col=row            result.data[rpos][1] = data[i][0];Â
            // same value            result.data[rpos][2] = data[i][2];        }Â
        // the above method ensures        // sorting of transpose matrix        // according to row-col value        return result;    }Â
    void multiply(sparse_matrix b)    {        if (col != b.row)        {Â
            // Invalid multiplication            cout << "Can't multiply, Invalid dimensions";            return;        }Â
        // transpose b to compare row        // and col values and to add them at the end        b = b.transpose();        int apos, bpos;Â
        // result matrix of dimension row X b.col        // however b has been transposed,        // hence row X b.row        sparse_matrix result(row, b.row);Â
        // iterate over all elements of A        for (apos = 0; apos < len;)        {Â
            // current row of result matrix            int r = data[apos][0];Â
            // iterate over all elements of B            for (bpos = 0; bpos < b.len;)            {Â
                // current column of result matrix                // data[,0] used as b is transposed                int c = b.data[bpos][0];Â
                // temporary pointers created to add all                // multiplied values to obtain current                // element of result matrix                int tempa = apos;                int tempb = bpos;Â
                int sum = 0;Â
                // iterate over all elements with                // same row and col value                // to calculate result[r]                while (tempa < len && data[tempa][0] == r &&                       tempb < b.len && b.data[tempb][0] == c)                {                    if (data[tempa][1] < b.data[tempb][1])Â
                        // skip a                        tempa++;Â
                    else if (data[tempa][1] > b.data[tempb][1])Â
                        // skip b                        tempb++;                    elseÂ
                        // same col, so multiply and increment                        sum += data[tempa++][2] *                              b.data[tempb++][2];                }Â
                // insert sum obtained in result[r]                // if its not equal to 0                if (sum != 0)                    result.insert(r, c, sum);Â
                while (bpos < b.len &&                        b.data[bpos][0] == c)Â
                    // jump to next column                    bpos++;            }            while (apos < len && data[apos][0] == r)Â
                // jump to next row                apos++;        }        result.print();    }Â
    // printing matrix    void print()    {        cout << "\nDimension: " << row << "x" << col;        cout << "\nSparse Matrix: \nRow\tColumn\tValue\n";Â
        for (int i = 0; i < len; i++)        {            cout << data[i][0] << "\t " << data[i][1]                  << "\t " << data[i][2] << endl;        }    }};Â
// Driver Codeint main(){Â
    // create two sparse matrices and insert values    sparse_matrix a(4, 4);    sparse_matrix b(4, 4);Â
    a.insert(1, 2, 10);    a.insert(1, 4, 12);    a.insert(3, 3, 5);    a.insert(4, 1, 15);    a.insert(4, 2, 12);    b.insert(1, 3, 8);    b.insert(2, 4, 23);    b.insert(3, 3, 9);    b.insert(4, 1, 20);    b.insert(4, 2, 25);Â
    // Output result    cout << "Addition: ";    a.add(b);    cout << "\nMultiplication: ";    a.multiply(b);    cout << "\nTranspose: ";    sparse_matrix atranspose = a.transpose();    atranspose.print();}Â
// This code is contributed// by Bharath Vignesh J K |
Java
// Java code to perform add,// multiply and transpose on sparse matricesÂ
public class sparse_matrix {Â
    // Maximum number of elements in matrix    int MAX = 100;Â
    // Array representation    // of sparse matrix    //[][0] represents row    //[][1] represents col    //[][2] represents value    int data[][] = new int[MAX][3];Â
    // dimensions of matrix    int row, col;Â
    // total number of elements in matrix    int len;Â
    public sparse_matrix(int r, int c)    {Â
        // initialize row        row = r;Â
        // initialize col        col = c;Â
        // initialize length to 0        len = 0;    }Â
    // insert elements into sparse matrix    public void insert(int r, int c, int val)    {Â
        // invalid entry        if (r > row || c > col) {            System.out.println("Wrong entry");        }Â
        else {Â
            // insert row value            data[len][0] = r;Â
            // insert col value            data[len][1] = c;Â
            // insert element's value            data[len][2] = val;Â
            // increment number of data in matrix            len++;        }    }Â
    public void add(sparse_matrix b)    {Â
        // if matrices don't have same dimensions        if (row != b.row || col != b.col) {            System.out.println("Matrices can't be added");        }Â
        else {Â
            int apos = 0, bpos = 0;            sparse_matrix result = new sparse_matrix(row, col);Â
            while (apos < len && bpos < b.len) {Â
                // if b's row and col is smaller                if (data[apos][0] > b.data[bpos][0] ||                   (data[apos][0] == b.data[bpos][0] &&                    data[apos][1] > b.data[bpos][1]))Â
                {Â
                    // insert smaller value into result                    result.insert(b.data[bpos][0],                                  b.data[bpos][1],                                  b.data[bpos][2]);Â
                    bpos++;                }Â
                // if a's row and col is smaller                else if (data[apos][0] < b.data[bpos][0] ||                 (data[apos][0] == b.data[bpos][0] &&                   data[apos][1] < b.data[bpos][1]))Â
                {Â
                    // insert smaller value into result                    result.insert(data[apos][0],                                  data[apos][1],                                  data[apos][2]);Â
                    apos++;                }Â
                else {Â
                    // add the values as row and col is same                    int addedval = data[apos][2] + b.data[bpos][2];Â
                    if (addedval != 0)                        result.insert(data[apos][0],                                      data[apos][1],                                      addedval);                    // then insert                    apos++;                    bpos++;                }            }Â
            // insert remaining elements            while (apos < len)                result.insert(data[apos][0],                              data[apos][1],                              data[apos++][2]);Â
            while (bpos < b.len)                result.insert(b.data[bpos][0],                              b.data[bpos][1],                              b.data[bpos++][2]);Â
            // print result            result.print();        }    }Â
    public sparse_matrix transpose()    {Â
        // new matrix with inversed row X col        sparse_matrix result = new sparse_matrix(col, row);Â
        // same number of elements        result.len = len;Â
        // to count number of elements in each column        int count[] = new int[col + 1];Â
        // initialize all to 0        for (int i = 1; i <= col; i++)            count[i] = 0;Â
        for (int i = 0; i < len; i++)            count[data[i][1]]++;Â
        int[] index = new int[col + 1];Â
        // to count number of elements having col smaller        // than particular iÂ
        // as there is no col with value < 1        index[1] = 0;Â
        // initialize rest of the indices        for (int i = 2; i <= col; i++)Â
            index[i] = index[i - 1] + count[i - 1];Â
        for (int i = 0; i < len; i++) {Â
            // insert a data at rpos and increment its value            int rpos = index[data[i][1]]++;Â
            // transpose row=col            result.data[rpos][0] = data[i][1];Â
            // transpose col=row            result.data[rpos][1] = data[i][0];Â
            // same value            result.data[rpos][2] = data[i][2];        }Â
        // the above method ensures        // sorting of transpose matrix        // according to row-col value        return result;    }Â
    public void multiply(sparse_matrix b)    {Â
        if (col != b.row) {Â
            // Invalid multiplication            System.out.println("Can't multiply, "                               + "Invalid dimensions");Â
            return;        }Â
        // transpose b to compare row        // and col values and to add them at the end        b = b.transpose();        int apos, bpos;Â
        // result matrix of dimension row X b.col        // however b has been transposed, hence row X b.row        sparse_matrix result = new sparse_matrix(row, b.row);Â
        // iterate over all elements of A        for (apos = 0; apos < len;) {Â
            // current row of result matrix            int r = data[apos][0];Â
            // iterate over all elements of B            for (bpos = 0; bpos < b.len;) {Â
                // current column of result matrix                // data[][0] used as b is transposed                int c = b.data[bpos][0];Â
                // temporary pointers created to add all                // multiplied values to obtain current                // element of result matrix                int tempa = apos;                int tempb = bpos;Â
                int sum = 0;Â
                // iterate over all elements with                // same row and col value                // to calculate result[r]                while (tempa < len && data[tempa][0] == r                       && tempb < b.len && b.data[tempb][0] == c) {Â
                    if (data[tempa][1] < b.data[tempb][1])Â
                        // skip a                        tempa++;Â
                    else if (data[tempa][1] > b.data[tempb][1])Â
                        // skip b                        tempb++;                    elseÂ
                        // same col, so multiply and increment                        sum += data[tempa++][2] * b.data[tempb++][2];                }Â
                // insert sum obtained in result[r]                // if its not equal to 0                if (sum != 0)                    result.insert(r, c, sum);Â
                while (bpos < b.len && b.data[bpos][0] == c)Â
                    // jump to next column                    bpos++;            }Â
            while (apos < len && data[apos][0] == r)Â
                // jump to next row                apos++;        }Â
        result.print();    }Â
    // printing matrix    public void print()    {        System.out.println("Dimension: " + row + "x" + col);        System.out.println("Sparse Matrix: \nRow Column Value");Â
        for (int i = 0; i < len; i++) {Â
            System.out.println(data[i][0] + " "                             + data[i][1] + " " + data[i][2]);        }    }Â
    public static void main(String args[])    {Â
        // create two sparse matrices and insert values        sparse_matrix a = new sparse_matrix(4, 4);        sparse_matrix b = new sparse_matrix(4, 4);Â
        a.insert(1, 2, 10);        a.insert(1, 4, 12);        a.insert(3, 3, 5);        a.insert(4, 1, 15);        a.insert(4, 2, 12);        b.insert(1, 3, 8);        b.insert(2, 4, 23);        b.insert(3, 3, 9);        b.insert(4, 1, 20);        b.insert(4, 2, 25);Â
        // Output result        System.out.println("Addition: ");        a.add(b);        System.out.println("\nMultiplication: ");        a.multiply(b);        System.out.println("\nTranspose: ");        sparse_matrix atranspose = a.transpose();        atranspose.print();    }}Â
// This code is contributed by Sudarshan Khasnis |
Python3
# Python3 code to perform add,# multiply and transpose on sparse matricesclass sparse_matrix :Â
    def __init__(self, r, c):             # Maximum number of elements in matrix        self.MAX = 100;                 # Array representation        # of sparse matrix        #[][0] represents row        #[][1] represents col        #[][2] represents value        self.data = [None for _ in range(self.MAX)]        for i in range(self.MAX):            self.data[i] = [None for _ in range(3)]Â
        # dimensions of matrix        self.row = r;        self.col = c;Â
        # total number of elements in matrix        self.len = 0;         # insert elements into sparse matrix    def insert(self, r, c, val):             # invalid entry        if (r > self.row or c > self.col) :            print("Wrong entry");        else :Â
            # insert row value            self.data[self.len][0] = r;Â
            # insert col value            self.data[self.len][1] = c;Â
            # insert element's value            self.data[self.len][2] = val;Â
            # increment number of data in matrix            self.len += 1;             def add(self, b):Â
        # if matrices don't have same dimensions        if (self.row != b.row or self.col != b.col) :            print("Matrices can't be added");        else:Â
            apos = 0;            bpos = 0;            result = sparse_matrix(self.row, self.col);Â
            while (apos < self.len and bpos < b.len):Â
                # if b's row and col is smaller                if (self.data[apos][0] > b.data[bpos][0] or (self.data[apos][0] == b.data[bpos][0] and self.data[apos][1] > b.data[bpos][1])):Â
                    # insert smaller value into result                    result.insert(b.data[bpos][0],                                  b.data[bpos][1],                                  b.data[bpos][2]);                    bpos += 1                                 # if a's row and col is smaller                elif (self.data[apos][0] < b.data[bpos][0] or (self.data[apos][0] == b.data[bpos][0] and self.data[apos][1] < b.data[bpos][1])):                                         # insert smaller value into result                    result.insert(self.data[apos][0], self.data[apos][1], self.data[apos][2]);                    apos += 1;                             else:Â
                    # add the values as row and col is same                    addedval = self.data[apos][2] + b.data[bpos][2];Â
                    if (addedval != 0):                        result.insert(self.data[apos][0], self.data[apos][1], addedval);                    # then insert                    apos += 1;                    bpos += 1;                             # insert remaining elements            while (apos < self.len):                result.insert(self.data[apos][0],self.data[apos][1], self.data[apos][2]);                apos += 1Â
            while (bpos < b.len):                result.insert(b.data[bpos][0], b.data[bpos][1], b.data[bpos][2]);                bpos += 1Â
            # print result            result.print();             def transpose(self):             # new matrix with inversed row X col        result = sparse_matrix(self.col, self.row);Â
        # same number of elements        result.len = self.len;Â
        # to count number of elements in each column        count = [None for _ in range(self.col + 1)];Â
        # initialize all to 0        for i in range(1, 1 + self.col):            count[i] = 0;Â
        for i in range(0, self.len):            count[self.data[i][1]] += 1Â
        index = [None for _ in range(self.col + 1)]Â
        # to count number of elements having col smaller        # than particular iÂ
        # as there is no col with value < 1        index[1] = 0;Â
        # initialize rest of the indices        for i in range(2, 1 + self.col):            index[i] = index[i - 1] + count[i - 1];Â
        for i in range(self.len): Â
            # insert a data at rpos and increment its value            rpos = index[self.data[i][1]]            index[self.data[i][1]] += 1Â
            # transpose row=col            result.data[rpos][0] = self.data[i][1];Â
            # transpose col=row            result.data[rpos][1] = self.data[i][0];Â
            # same value            result.data[rpos][2] = self.data[i][2];                 # the above method ensures        # sorting of transpose matrix        # according to row-col value        return result;         def multiply(self, b):        if (self.col != b.row):Â
            # Invalid multiplication            print("Can't multiply, Invalid dimensions");            return;                 # transpose b to compare row        # and col values and to add them at the end        b = b.transpose();Â
        # result matrix of dimension row X b.col        # however b has been transposed, hence row X b.row        result = sparse_matrix(self.row, b.row);Â
        # iterate over all elements of A        for apos in range(self.len): Â
            # current row of result matrix            r = self.data[apos][0];Â
            # iterate over all elements of B            for bpos in range(b.len): Â
                # current column of result matrix                # data[][0] used as b is transposed                c = b.data[bpos][0];Â
                # temporary pointers created to add all                # multiplied values to obtain current                # element of result matrix                tempa = apos;                tempb = bpos;                sum = 0;Â
                # iterate over all elements with                # same row and col value                # to calculate result[r]                while (tempa < self.len and self.data[tempa][0] == r and tempb < b.len and b.data[tempb][0] == c):Â
                    if (self.data[tempa][1] < b.data[tempb][1]):Â
                        # skip a                        tempa += 1Â
                    elif (self.data[tempa][1] > b.data[tempb][1]):Â
                        # skip b                        tempb += 1                    else:Â
                        # same col, so multiply and                        # increment                        sum += self.data[tempa][2] * b.data[tempb][2];                        tempa += 1                        tempb += 1                                 # insert sum obtained in result[r]                # if its not equal to 0                if (sum != 0):                    result.insert(r, c, sum);                while (bpos < b.len and b.data[bpos][0] == c):Â
                    # jump to next column                    bpos += 1                         while (apos < self.len and self.data[apos][0] == r):Â
                # jump to next row                apos += 1                 result.print();         # printing matrix    def print(self):        print("Dimension:", self.row, "x", self.col);        print("Sparse Matrix: \nRow Column Value");             for i in range(self.len):             print(self.data[i][0], self.data[i][1], self.data[i][2]);         # create two sparse matrices and insert valuesa = sparse_matrix(4, 4);b = sparse_matrix(4, 4);Â
a.insert(1, 2, 10);a.insert(1, 4, 12);a.insert(3, 3, 5);a.insert(4, 1, 15);a.insert(4, 2, 12);b.insert(1, 3, 8);b.insert(2, 4, 23);b.insert(3, 3, 9);b.insert(4, 1, 20);b.insert(4, 2, 25);Â
# Output resultprint("Addition: ");a.add(b);print("\nMultiplication: ");a.multiply(b);print("\nTranspose: ");atranspose = a.transpose();atranspose.print();Â
# This code is contributed by phasing17 |
C#
// C# code to perform add, // multiply and transpose on sparse matrices Â
public class sparse_matrix { Â
    // Maximum number of elements in matrix     static int MAX = 100; Â
    // Array representation     // of sparse matrix     //[,0] represents row     //[,1] represents col     //[,2] represents value     int[,] data = new int[MAX,3]; Â
    // dimensions of matrix     int row, col; Â
    // total number of elements in matrix     int len; Â
    public sparse_matrix(int r, int c)     { Â
        // initialize row         row = r; Â
        // initialize col         col = c; Â
        // initialize length to 0         len = 0;     } Â
    // insert elements into sparse matrix     public void insert(int r, int c, int val)     { Â
        // invalid entry         if (r > row || c > col) {             System.Console.WriteLine("Wrong entry");         } Â
        else { Â
            // insert row value             data[len,0] = r; Â
            // insert col value             data[len,1] = c; Â
            // insert element's value             data[len,2] = val; Â
            // increment number of data in matrix             len++;         }     } Â
    public void add(sparse_matrix b)     { Â
        // if matrices don't have same dimensions         if (row != b.row || col != b.col) {             System.Console.WriteLine("Matrices can't be added");         } Â
        else { Â
            int apos = 0, bpos = 0;             sparse_matrix result = new sparse_matrix(row, col); Â
            while (apos < len && bpos < b.len) { Â
                // if b's row and col is smaller                 if (data[apos,0] > b.data[bpos,0] ||                 (data[apos,0] == b.data[bpos,0] &&                 data[apos,1] > b.data[bpos,1])) Â
                { Â
                    // insert smaller value into result                     result.insert(b.data[bpos,0],                                 b.data[bpos,1],                                 b.data[bpos,2]); Â
                    bpos++;                 } Â
                // if a's row and col is smaller                 else if (data[apos,0] < b.data[bpos,0] ||                 (data[apos,0] == b.data[bpos,0] &&                 data[apos,1] < b.data[bpos,1])) Â
                { Â
                    // insert smaller value into result                     result.insert(data[apos,0],                                 data[apos,1],                                 data[apos,2]); Â
                    apos++;                 } Â
                else { Â
                    // add the values as row and col is same                     int addedval = data[apos,2] + b.data[bpos,2]; Â
                    if (addedval != 0)                         result.insert(data[apos,0],                                     data[apos,1],                                     addedval);                     // then insert                     apos++;                     bpos++;                 }             } Â
            // insert remaining elements             while (apos < len)                 result.insert(data[apos,0],                             data[apos,1],                             data[apos++,2]); Â
            while (bpos < b.len)                 result.insert(b.data[bpos,0],                             b.data[bpos,1],                             b.data[bpos++,2]); Â
            // print result             result.print();         }     } Â
    public sparse_matrix transpose()     { Â
        // new matrix with inversed row X col         sparse_matrix result = new sparse_matrix(col, row); Â
        // same number of elements         result.len = len; Â
        // to count number of elements in each column         int[] count = new int[col + 1]; Â
        // initialize all to 0         for (int i = 1; i <= col; i++)             count[i] = 0; Â
        for (int i = 0; i < len; i++)             count[data[i,1]]++; Â
        int[] index = new int[col + 1]; Â
        // to count number of elements having col smaller         // than particular i Â
        // as there is no col with value < 1         index[1] = 0; Â
        // initialize rest of the indices         for (int i = 2; i <= col; i++) Â
            index[i] = index[i - 1] + count[i - 1]; Â
        for (int i = 0; i < len; i++) { Â
            // insert a data at rpos and increment its value             int rpos = index[data[i,1]]++; Â
            // transpose row=col             result.data[rpos,0] = data[i,1]; Â
            // transpose col=row             result.data[rpos,1] = data[i,0]; Â
            // same value             result.data[rpos,2] = data[i,2];         } Â
        // the above method ensures         // sorting of transpose matrix         // according to row-col value         return result;     } Â
    public void multiply(sparse_matrix b)     { Â
        if (col != b.row) { Â
            // Invalid multiplication             System.Console.WriteLine("Can't multiply, "                            + "Invalid dimensions"); Â
            return;         } Â
        // transpose b to compare row         // and col values and to add them at the end         b = b.transpose();         int apos, bpos; Â
        // result matrix of dimension row X b.col         // however b has been transposed, hence row X b.row         sparse_matrix result = new sparse_matrix(row, b.row); Â
        // iterate over all elements of A         for (apos = 0; apos < len;) { Â
            // current row of result matrix             int r = data[apos,0]; Â
            // iterate over all elements of B             for (bpos = 0; bpos < b.len;) { Â
                // current column of result matrix                 // data[,0] used as b is transposed                 int c = b.data[bpos,0]; Â
                // temporary pointers created to add all                 // multiplied values to obtain current                 // element of result matrix                 int tempa = apos;                 int tempb = bpos; Â
                int sum = 0; Â
                // iterate over all elements with                 // same row and col value                 // to calculate result[r]                 while (tempa < len && data[tempa,0] == r                     && tempb < b.len && b.data[tempb,0] == c) { Â
                    if (data[tempa,1] < b.data[tempb,1]) Â
                        // skip a                         tempa++; Â
                    else if (data[tempa,1] > b.data[tempb,1]) Â
                        // skip b                         tempb++;                     elseÂ
                        // same col, so multiply and increment                         sum += data[tempa++,2] * b.data[tempb++,2];                 } Â
                // insert sum obtained in result[r]                 // if its not equal to 0                 if (sum != 0)                     result.insert(r, c, sum); Â
                while (bpos < b.len && b.data[bpos,0] == c) Â
                    // jump to next column                     bpos++;             } Â
            while (apos < len && data[apos,0] == r) Â
                // jump to next row                 apos++;         } Â
        result.print();     } Â
    // printing matrix     public void print()     {         System.Console.WriteLine("Dimension: " + row + "x" + col);         System.Console.WriteLine("Sparse Matrix: \nRow Column Value"); Â
        for (int i = 0; i < len; i++) { Â
            System.Console.WriteLine(data[i,0] + " "                            + data[i,1] + " " + data[i,2]);         }     } Â
    public static void Main()     { Â
        // create two sparse matrices and insert values         sparse_matrix a = new sparse_matrix(4, 4);         sparse_matrix b = new sparse_matrix(4, 4); Â
        a.insert(1, 2, 10);         a.insert(1, 4, 12);         a.insert(3, 3, 5);         a.insert(4, 1, 15);         a.insert(4, 2, 12);         b.insert(1, 3, 8);         b.insert(2, 4, 23);         b.insert(3, 3, 9);         b.insert(4, 1, 20);         b.insert(4, 2, 25); Â
        // Output result         System.Console.WriteLine("Addition: ");         a.add(b);         System.Console.WriteLine("\nMultiplication: ");         a.multiply(b);         System.Console.WriteLine("\nTranspose: ");         sparse_matrix atranspose = a.transpose();         atranspose.print();     } } Â
// This code is contributed by mits |
Javascript
// JavaScript code to perform add,// multiply and transpose on sparse matricesclass sparse_matrix {Â
    constructor(r, c)    {             // Maximum number of elements in matrix        this.MAX = 100;                 // Array representation        // of sparse matrix        //[][0] represents row        //[][1] represents col        //[][2] represents value        this.data = new Array(this.MAX);        for (var i = 0; i < this.MAX; i++)            this.data[i] = new Array(3);Â
        // dimensions of matrix        this.row = r;        this.col = c;Â
        // total number of elements in matrix        this.len = 0;    }Â
    // insert elements into sparse matrix    insert(r, c, val)    {Â
        // invalid entry        if (r > this.row || c > this.col) {            console.log("Wrong entry");        }Â
        else {Â
            // insert row value            this.data[this.len][0] = r;Â
            // insert col value            this.data[this.len][1] = c;Â
            // insert element's value            this.data[this.len][2] = val;Â
            // increment number of data in matrix            this.len++;        }    }Â
    add(b)    {Â
        // if matrices don't have same dimensions        if (this.row != b.row || this.col != b.col) {            console.log("Matrices can't be added");        }Â
        else {Â
            let apos = 0, bpos = 0;            let result                = new sparse_matrix(this.row, this.col);Â
            while (apos < this.len && bpos < b.len) {Â
                // if b's row and col is smaller                if (this.data[apos][0] > b.data[bpos][0]                    || (this.data[apos][0]                            == b.data[bpos][0]                        && this.data[apos][1]                               > b.data[bpos][1]))Â
                {Â
                    // insert smaller value into result                    result.insert(b.data[bpos][0],                                  b.data[bpos][1],                                  b.data[bpos][2]);Â
                    bpos++;                }Â
                // if a's row and col is smaller                else if (this.data[apos][0]                             < b.data[bpos][0]                         || (this.data[apos][0]                                 == b.data[bpos][0]                             && this.data[apos][1]                                    < b.data[bpos][1]))Â
                {Â
                    // insert smaller value into result                    result.insert(this.data[apos][0],                                  this.data[apos][1],                                  this.data[apos][2]);Â
                    apos++;                }Â
                else {Â
                    // add the values as row and col is same                    let addedval = this.data[apos][2]                                   + b.data[bpos][2];Â
                    if (addedval != 0)                        result.insert(this.data[apos][0],                                      this.data[apos][1],                                      addedval);                    // then insert                    apos++;                    bpos++;                }            }Â
            // insert remaining elements            while (apos < this.len)                result.insert(this.data[apos][0],                              this.data[apos][1],                              this.data[apos++][2]);Â
            while (bpos < b.len)                result.insert(b.data[bpos][0],                              b.data[bpos][1],                              b.data[bpos++][2]);Â
            // print result            result.print();        }    }Â
    transpose()    {Â
        // new matrix with inversed row X col        let result = new sparse_matrix(this.col, this.row);Â
        // same number of elements        result.len = this.len;Â
        // to count number of elements in each column        let count = new Array(this.col + 1);Â
        // initialize all to 0        for (var i = 1; i <= this.col; i++)            count[i] = 0;Â
        for (var i = 0; i < this.len; i++)            count[this.data[i][1]]++;Â
        let index = new Array(this.col + 1);Â
        // to count number of elements having col smaller        // than particular iÂ
        // as there is no col with value < 1        index[1] = 0;Â
        // initialize rest of the indices        for (var i = 2; i <= this.col; i++)Â
            index[i] = index[i - 1] + count[i - 1];Â
        for (var i = 0; i < this.len; i++) {Â
            // insert a data at rpos and increment its value            var rpos = index[this.data[i][1]]++;Â
            // transpose row=col            result.data[rpos][0] = this.data[i][1];Â
            // transpose col=row            result.data[rpos][1] = this.data[i][0];Â
            // same value            result.data[rpos][2] = this.data[i][2];        }Â
        // the above method ensures        // sorting of transpose matrix        // according to row-col value        return result;    }Â
    multiply(b)    {Â
        if (this.col != b.row) {Â
            // Invalid multiplication            console.log("Can't multiply, "                        + "Invalid dimensions");Â
            return;        }Â
        // transpose b to compare row        // and col values and to add them at the end        b = b.transpose();        let apos, bpos;Â
        // result matrix of dimension row X b.col        // however b has been transposed, hence row X b.row        let result = new sparse_matrix(this.row, b.row);Â
        // iterate over all elements of A        for (apos = 0; apos < this.len;) {Â
            // current row of result matrix            let r = this.data[apos][0];Â
            // iterate over all elements of B            for (bpos = 0; bpos < b.len;) {Â
                // current column of result matrix                // data[][0] used as b is transposed                let c = b.data[bpos][0];Â
                // temporary pointers created to add all                // multiplied values to obtain current                // element of result matrix                let tempa = apos;                let tempb = bpos;Â
                let sum = 0;Â
                // iterate over all elements with                // same row and col value                // to calculate result[r]                while (tempa < this.len                       && this.data[tempa][0] == r                       && tempb < b.len                       && b.data[tempb][0] == c) {Â
                    if (this.data[tempa][1]                        < b.data[tempb][1])Â
                        // skip a                        tempa++;Â
                    else if (this.data[tempa][1]                             > b.data[tempb][1])Â
                        // skip b                        tempb++;                    elseÂ
                        // same col, so multiply and                        // increment                        sum += this.data[tempa++][2]                               * b.data[tempb++][2];                }Â
                // insert sum obtained in result[r]                // if its not equal to 0                if (sum != 0)                    result.insert(r, c, sum);Â
                while (bpos < b.len && b.data[bpos][0] == c)Â
                    // jump to next column                    bpos++;            }Â
            while (apos < this.len                   && this.data[apos][0] == r)Â
                // jump to next row                apos++;        }Â
        result.print();    }Â
    // printing matrix    print()    {        console.log("Dimension: " + this.row + "x"                    + this.col);        console.log("Sparse Matrix: \nRow Column Value");Â
        for (var i = 0; i < this.len; i++) {Â
            console.log(this.data[i][0] + " "                        + this.data[i][1] + " "                        + this.data[i][2]);        }    }};Â
// create two sparse matrices and insert valueslet a = new sparse_matrix(4, 4);let b = new sparse_matrix(4, 4);Â
a.insert(1, 2, 10);a.insert(1, 4, 12);a.insert(3, 3, 5);a.insert(4, 1, 15);a.insert(4, 2, 12);b.insert(1, 3, 8);b.insert(2, 4, 23);b.insert(3, 3, 9);b.insert(4, 1, 20);b.insert(4, 2, 25);Â
// Output resultconsole.log("Addition: ");a.add(b);console.log("\nMultiplication: ");a.multiply(b);console.log("\nTranspose: ");let atranspose = a.transpose();atranspose.print();Â
// This code is contributed by phasing17 |
Addition: Dimension: 4x4 Sparse Matrix: Row Column Value 1 2 10 1 3 8 1 4 12 2 4 23 3 3 14 4 1 35 4 2 37 Multiplication: Dimension: 4x4 Sparse Matrix: Row Column Value 1 1 240 1 2 300 1 4 230 3 3 45 4 3 120 4 4 276 Transpose: Dimension: 4x4 Sparse Matrix: Row Column Value 1 4 15 2 1 10 2 4 12 3 3 5 4 1 12
Worst case time complexity: Addition operation traverses the matrices linearly, hence, has a time complexity of O(n), where n is the number of non-zero elements in the larger matrix amongst the two. Transpose has a time complexity of O(n+m), where n is the number of columns and m is the number of non-zero elements in the matrix. Multiplication, however, has a time complexity of O(x*n + y*m), where (x, m) is number of columns and terms in the second matrix; and (y, n) is number of rows and terms in the first matrix.
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