numpy.pmt(rate, pmt, pv, fv, when = ‘end’) : This financial function helps user to compute number of periodic payments.
Parameters :
rate : [scalar or (M, )array] Rate of interest as decimal (not per cent) per period
pmt : [scalar or (M, )array] Payment value
fv : [scalar or (M, )array] Future value
pv : [scalar or (M, )array] present value
when : at the beginning (when = {‘begin’, 1}) or the end (when = {‘end’, 0}) of each period. Default is {‘end’, 0}.Return : Number of periodic payments.
Equation being solved :
fv + pv*(1+rate)**nper + pmt*(1 + rate*when)/rate*((1 + rate)**nper – 1) == 0
or when rate == 0
fv + pv + pmt * nper == 0
Code:
# Python program explaining # pmt() function import numpy as np ''' Question : how much time would it take to pay-off a loan of $10, 000 at 10 % annual rate of interest, if we had $100 to pay each month ? ''' # rate pmt pv Solution = np.nper(0.1 / 12, -100, 10000) # Here fv = 0 ; Also Default value of fv = 0 print("Solution - No. of periods : % f months" %(Solution)) |
Output:
Solution - No. of periods : 215.905777 months
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