numpy.core.defchararray.count(arr, substring, start=0, end=None): Counts for the non-overlapping occurrence of sub-string in the specified range.
Parameters:
arr : array-like or string to be searched.
substring : substring to search for.
start, end : [int, optional] Range to search in.Returns : An integer array with the number of non-overlapping occurrences of sub-string.
Code #1:
# Python Program illustrating # numpy.char.count() method import numpy as np # 2D array arr = ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz'] print ("arr : ", arr) print ("Count of 'tt'", np.char.count(arr, 'tt'))print ("Count of 'tt'", np.char.count(arr, 'tt', start = 0))print ("Count of 'tt'", np.char.count(arr, 'tt', start = 8)) |
Output:
arr : ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz'] Count of 'tt' [2 2 1 0] Count of 'tt' [2 2 1 0] Count of 'tt' [1 2 1 0]
Code #2:
# Python Program illustrating # numpy.char.count() method import numpy as np # 2D array arr = ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz'] print ("arr : ", arr) print ("Count of 'Aa'", np.char.count(arr, 'Aa'))print ("Count of 'Aa'", np.char.count(arr, 'Aa', start = 8)) |
Output:
arr : ['vdsdsttetteteAAAa', 'AAAAAAAaattttds', 'AAaaxxxxtt', 'AAaaXDSDdscz'] Count of 'Aa' [1 1 1 1] Count of 'Aa' [1 0 0 0]
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