Isoweekday() is a method of the DateTime class that tells the day of the given date. It returns an integer that corresponds to a particular day.
Syntax: datetime.isoweekday()
Parameters: None
Return Value: It returns an integer which corresponds to a day as per the table
| Integer Returned | Day of the week |
|---|---|
| 1 | Monday |
| 2 | Tuesday |
| 3 | Wednesday |
| 4 | Thursday |
| 5 | Friday |
| 6 | Saturday |
| 7 | Sunday |
Example 1: Print the day of the current date.
Python3
# importing the datetime moduleimport datetime# Creating an dictionary with the return# value as keys and the day as the value# This is used to retrieve the day of the# week using the return value of the# isoweekday() functionweekdays = {1: "Monday", 2: "Tuesday", 3: "Wednesday", 4: "Thursday", 5: "Friday", 6: "Saturday", 7: "Sunday"}# Getting current date using today()# function of the datetime classtodays_date = datetime.date.today()print("Today's date is :", todays_date)# Using the isoweekday() function to# retrieve the day of the given dateday = todays_date.isoweekday()print("The date", todays_date, "falls on", weekdays[day]) |
Output:
Today's date is : 2021-07-27 The date 2021-07-27 falls on Tuesday
Example 2: Get the day of the week for today’s date from 2010 to the current year
Python3
# importing the datetime moduleimport datetime# Creating an dictionary with the return# value as keys and the day as the value# This is used to retrieve the day of the# week using the return value of the # isoweekday() functionweekdays = {1: "Monday", 2: "Tuesday", 3: "Wednesday", 4: "Thursday", 5: "Friday", 6: "Saturday", 7: "Sunday"}# Getting current year using today() function# of the datetime class and the year attributeToday = datetime.date.today()current_year = Today.yearfor i in range(2010, current_year+1): # Printing the day of the year # by first creating an datetime object # for the starting day of the year and # then we use isoweekday # to get the value and we use the # weekdays to retrieve the day of the year print("The {}/{} in the year {} has fallen on {}".\ format(Today.month, Today.day, i, weekdays[datetime.date(i, Today.month, Today.day).isoweekday()])) |
Output:
The 7/28 in the year 2010 has fallen on Wednesday
The 7/28 in the year 2011 has fallen on Thursday
The 7/28 in the year 2012 has fallen on Saturday
The 7/28 in the year 2013 has fallen on Sunday
The 7/28 in the year 2014 has fallen on Monday
The 7/28 in the year 2015 has fallen on Tuesday
The 7/28 in the year 2016 has fallen on Thursday
The 7/28 in the year 2017 has fallen on Friday
The 7/28 in the year 2018 has fallen on Saturday
The 7/28 in the year 2019 has fallen on Sunday
The 7/28 in the year 2020 has fallen on Tuesday
The 7/28 in the year 2021 has fallen on Wednesday
