Given a number N. The task is to write a program to find the Nth term in the below series:
1, 1, 2, 6, 24…
Examples:
Input: 3
Output: 2
For N = 3
Nth term = (N-1)!
= 2
Input: 5
Output: 24
Nth term of the series is given by below formula:
Nth term = ( N-1)!
Below is the required implementation:
C++
// CPP program to find N-th term of the series:// 1, 1, 2, 6, 24...#include <iostream>using namespace std;// calculate Nth term of seriesint nthTerm(int N){ if (N <= 1) return 1; int i, fact = 1; for (i = 1; i < N; i++) fact = fact * i; return fact;}// Driver Functionint main(){ int N = 3; cout << nthTerm(N); return 0;} |
Java
// Java program to find the Nth termimport java.io.*;// calculate Nth term of this series// 1, 1, 2, 6, 24...class Nth { public int nthTerm(int N) { // By using above formula if (N <= 1) return 1; int i, fact = 1; for (i = 1; i < N; i++) fact = fact * i; return fact; }}// Main class for main methodclass GFG { public static void main(String[] args) { int N = 3; // create object of Class Nth Nth a = new Nth(); // call and print Nth term System.out.println(a.nthTerm(N)); }} |
Python 3
# Python 3 program to find # N-th term of the series: # 1, 1, 2, 6, 24... # Function to calculate # Nth term of series def nthTerm(n) : if n <= 1 : return 1 fact = 1 for i in range(1, N) : fact = fact * i return fact# Driver codeif __name__ == "__main__" : N = 3 # function calling print(nthTerm(N))# This code is contributed # by ANKITRAI1 |
C#
// C# program to find the // Nth term of the series// 1, 1, 2, 6, 24...using System;// calculate Nth term class GFG {public int nthTerm(int N){ // By using above formula if (N <= 1) return 1; int i, fact = 1; for (i = 1; i < N; i++) fact = fact * i; return fact;}// Driver Codepublic static void Main(){ int N = 3; // create object of Class GFG GFG a = new GFG(); // call and print Nth term Console.Write(a.nthTerm(N));}}// This code is contributed // by ChitraNayal |
PHP
<?php// PHP program to find N-th // term of the series:// 1, 1, 2, 6, 24...// calculate Nth term of seriesfunction nthTerm($N){ if ($N <= 1) return 1; $fact = 1; for ($i = 1; $i < $N; $i++) $fact = $fact * $i; return $fact;}// Driver Code$N = 3;echo nthTerm($N);// This code is contributed // by ChitraNayal?> |
Javascript
<script>// JavaScript program to find N-th term of the series:// 1, 1, 2, 6, 24...// calculate Nth term of seriesfunction nthTerm( N){ if (N <= 1) return 1; let i, fact = 1; for (i = 1; i < N; i++) fact = fact * i; return fact;}// Driver Function let N = 3; document.write(nthTerm(N)); // This code contributed by Rajput-Ji</script> |
Output:
2
Time Complexity: O(N), where N represents the given integer.
Auxiliary Space: O(1), no extra space is required, so it is a constant.
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