Given two arrays A[] and B[], the task is to choose two elements X and Y such that X belongs to A[] and Y belongs to B[] and (X + Y) must not be present in any of the array.
Examples:
Input: A[] = {3, 2, 2}, B[] = {1, 5, 7, 7, 9}
Output: 3 9
3 + 9 = 12 and 12 is not present in
any of the given arrays.
Input: A[] = {1, 3, 5, 7}, B[] = {7, 5, 3, 1}
Output: 7 7
Approach: Choose X as the maximum element from A[] and Y as the maximum element from B[]. Now, it is obvious that (X + Y) will be greater than the maximum of both the arrays i.e. it will not be present in any of the arrays.
Below is the implementation of the above approach:
C++
// C++ implementation of the approach#include <bits/stdc++.h>using namespace std;// Function to find the numbers from// the given arrays such that their// sum is not present in any// of the given arrayvoid findNum(int a[], int n, int b[], int m){ // Find the maximum element // from both the arrays int x = *max_element(a, a + n); int y = *max_element(b, b + m); cout << x << " " << y;}// Driver codeint main(){ int a[] = { 3, 2, 2 }; int n = sizeof(a) / sizeof(int); int b[] = { 1, 5, 7, 7, 9 }; int m = sizeof(b) / sizeof(int); findNum(a, n, b, m); return 0;} |
Java
// Java implementation of the approachclass GFG{ // find maximum element in an arraystatic int max_element(int a[], int n){ int m = Integer.MIN_VALUE; for(int i = 0; i < n; i++) m = Math.max(m, a[i]); return m;}// Function to find the numbers from// the given arrays such that their// sum is not present in any// of the given arraystatic void findNum(int a[], int n, int b[], int m){ // Find the maximum element // from both the arrays int x = max_element(a, n); int y = max_element(b, m); System.out.print(x + " " + y);}// Driver codepublic static void main(String args[]){ int a[] = { 3, 2, 2 }; int n = a.length; int b[] = { 1, 5, 7, 7, 9 }; int m = b.length; findNum(a, n, b, m);}}// This code is contributed by Arnub Kundu |
Python3
# Python3 implementation of the approach # Function to find the numbers from # the given arrays such that their # sum is not present in any # of the given array def findNum(a, n, b, m) : # Find the maximum element # from both the arrays x = max(a); y = max(b); print(x, y); # Driver code if __name__ == "__main__" : a = [ 3, 2, 2 ]; n = len(a); b = [ 1, 5, 7, 7, 9 ]; m = len(b); findNum(a, n, b, m);# This code is contributed by AnkitRai01 |
C#
// C# implementation of the approachusing System;class GFG{ // find maximum element in an array static int max_element(int []a, int n) { int m = int.MinValue; for(int i = 0; i < n; i++) m = Math.Max(m, a[i]); return m; } // Function to find the numbers from // the given arrays such that their // sum is not present in any // of the given array static void findNum(int []a, int n, int []b, int m) { // Find the maximum element // from both the arrays int x = max_element(a, n); int y = max_element(b, m); Console.Write(x + " " + y); } // Driver code public static void Main() { int []a = { 3, 2, 2 }; int n = a.Length; int []b = { 1, 5, 7, 7, 9 }; int m = b.Length; findNum(a, n, b, m); }}// This code is contributed by kanugargng |
Javascript
<script>// Javascript implementation of the approach// Function to find the numbers from// the given arrays such that their// sum is not present in any// of the given arrayfunction findNum(a, n, b, m){ // Find the maximum element // from both the arrays var x = a.reduce(function(a, b) { return Math.max(a, b); }); var y = b.reduce(function(a, b) { return Math.max(a, b); }); document.write(x + " " + y);}// Driver codevar a = [ 3, 2, 2 ];var n = a.length;var b = [ 1, 5, 7, 7, 9 ]var m = b.length;findNum(a, n, b, m);// This code is contributed by rutvik_56.</script> |
Output:
3 9
Time Complexity: O(n)
Auxiliary Space: O(1)
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