How many times is the below loop executed?
for(int i=0; i < n; i++) { for(int j=0; j < (2*i); j+=(i/2)) { cout<<"Hello Geeks"; } } |
(A) O(n)
(B) Infinite times
(C) O(n2)
(D) O(nlogn)
Answer: (B)
Explanation: At the second iteration of the outer loop, i.e. when i = 1, the inner loop will become an infinite loop as the increment condition is j = j+(i/2) and for i = 1, i/2 = 0.
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