See this for detailed description. In Java, parameters are always passed by value. For example, following program prints i = 10, j = 20.
java
// Test.javapublic class Test {// swap() doesn't swap i and jpublic static void swap(Integer i, Integer j) { Integer temp = new Integer(i); i = j; j = temp;}public static void main(String[] args) { Integer i = new Integer(10); Integer j = new Integer(20); swap(i, j); System.out.println("i = " + i + ", j = " + j);}} |
Output
i = 10, j = 20
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
… [Trackback]
[…] Read More here to that Topic: geeksforgeeks.org/how-are-parameters-passed-in-java/ […]