Periodic Binary String: A Binary string is called periodic if it can be written as a repetition of a binary string of smaller or same length. For example, 101010 is a periodic binary string with period 10 as we can get the string by repeatedly appending 10 to itself. In general, the string S with period P means, Si is equal to Si + P.
Problem: Given a binary string S, the task is to find the periodic string with minimum possible period with the following additional conditions
1) The given string S should be a subsequence of the result
2) Length of the result should not be more than twice the length of input string.
Examples:
Input:S = “01”
Output:0101
Explanation:The output string has period as 2 and has given string as subsequence.Input :S = “111”
Output :111
Explanation:The output string has period as 1.Input:S = “110”
Output: 101010
Explanation:The output string has period as 2 and has given string as subsequence. Please note that 110110 is not answer because the period length is more.
Approach:
The main idea depends on two possibilities:
- If the string consists all 1s or all 0s, the answer is the given string S itself having period as 1.
- If the string consists of dissimilar elements, find the string with period 2 and having length as twice the length of given string S
Below is the implementation of the above approach:
C++
// C++ implementation to find the // periodic string with minimum period #include <bits/stdc++.h> using namespace std; // Function to find the periodic string // with minimum period void findPeriodicString(string S) { int l = 2 * S.length(); int count = 0; for ( int i = 0; i < S.length(); i++) { if (S[i] == '1' ) count++; } // Print the string S if it // consists of similar elements if (count == S.length() || count == 0) cout << S << "\n" ; // Find the required periodic // string with period 2 else { char arr[l]; for ( int i = 0; i < l; i += 2) { arr[i] = '1' ; arr[i + 1] = '0' ; } for ( int i = 0; i < l; i++) cout << arr[i]; cout << "\n" ; } } // Driver Code int main() { string S = "1111001" ; findPeriodicString(S); return 0; } |
Java
// Java implementation to find the // periodic string with minimum period class GFG{ // Function to find the periodic string // with minimum period static void findPeriodicString(String S) { int l = 2 * S.length(); int count = 0 ; for ( int i = 0 ; i < S.length(); i++) { if (S.charAt(i) == '1' ) count++; } // Print the string S if it // consists of similar elements if (count == S.length() || count == 0 ) System.out.println(S); // Find the required periodic // string with period 2 else { char arr[] = new char [l]; for ( int i = 0 ; i < l; i += 2 ) { arr[i] = '1' ; arr[i + 1 ] = '0' ; } for ( int i = 0 ; i < l; i++) System.out.print(arr[i]); System.out.println(); } } // Driver Code public static void main (String[] args) { String S = "1111001" ; findPeriodicString(S); } } // This code is contributed by chitranayal |
Python3
# Python3 implementation to find the # periodic with minimum period # Function to find the periodic string # with minimum period def findPeriodicString(S): l = 2 * len (S) count = 0 for i in range ( len (S)): if (S[i] = = '1' ): count + = 1 # Print the S if it # consists of similar elements if (count = = len (S) or count = = 0 ): print (S) # Find the required periodic # with period 2 else : arr = [ '0' ] * l for i in range ( 0 , l, 2 ): arr[i] = '1' arr[i + 1 ] = '0' for i in range (l): print (arr[i],end = "") # Driver Code if __name__ = = '__main__' : S = "1111001" findPeriodicString(S) # This code is contributed by mohit kumar 29 |
C#
// C# implementation to find the // periodic string with minimum period using System; class GFG{ // Function to find the periodic string // with minimum period static void findPeriodicString( string S) { int l = 2 * S.Length; int count = 0; for ( int i = 0; i < S.Length; i++) { if (S[i] == '1' ) count++; } // Print the string S if it // consists of similar elements if (count == S.Length || count == 0) Console.WriteLine(S); // Find the required periodic // string with period 2 else { char [] arr = new char [l]; for ( int i = 0; i < l; i += 2) { arr[i] = '1' ; arr[i + 1] = '0' ; } for ( int i = 0; i < l; i++) Console.Write(arr[i]); Console.WriteLine(); } } // Driver code public static void Main () { string S = "1111001" ; findPeriodicString(S); } } // This code is contributed by sanjoy_62 |
Javascript
<script> // Javascript implementation to find the // periodic string with minimum period // Function to find the periodic string // with minimum period function findPeriodicString(S) { let l = 2 * S.length; let count = 0; for (let i = 0; i < S.length; i++) { if (S[i] == '1' ) count++; } // Print the string S if it // consists of similar elements if (count == S.length || count == 0) document.write(S + "<br>" ); // Find the required periodic // string with period 2 else { let arr = new Array(l); for (let i = 0; i < l; i += 2) { arr[i] = '1' ; arr[i + 1] = '0' ; } for (let i = 0; i < l; i++) document.write(arr[i]); document.write( "<br>" ); } } // Driver Code let S = "1111001" ; findPeriodicString(S); // This code is contributed by avanitrachhadiya2155 </script> |
10101010101010
Time Complexity: O(N)
Auxiliary Space: O(2*N)
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