The getName()function is a part of java.util.zip package. The function returns the path name of the ZipFile object.
Function Signature:
public String getName()
Syntax:
zip_file.getName();
Parameters: The function does not require any parameters
Return value: The function returns a string, which is the path name of the zip file
Exceptions: The function does not throw any exceptions.
Below programs illustrates the use of getName() function
Example 1: Create a file named zip_file and get the name using getName() function. “file.zip” is a zip file present in f: directory.
// Java program to demonstrate the// use of getName() function import java.util.zip.*; public class solution { public static void main(String args[]) { try { // Create a Zip File ZipFile zip_file = new ZipFile("f:\\file.zip"); // Display the name of the zip file // using getName() function System.out.println(zip_file.getName()); } catch (Exception e) { System.out.println(e.getMessage()); } }} |
Output:
f:\file.zip
Example 2: Create a file named zip_file and get the name using getName() function. “file1.zip” is a non-existent zip file in f: directory.
// Java program to demonstrate the// use of getName() function import java.util.zip.*; public class solution { public static void main(String args[]) { try { // Create a Zip File ZipFile zip_file = new ZipFile("f:\\file1.zip"); // Display the name of the zip file // using getName() function System.out.println(zip_file.getName()); } catch (Exception e) { System.out.println(e.getMessage()); } }} |
Output:
f:\file1.zip (The system cannot find the file specified)
Reference: https://docs.oracle.com/javase/7/docs/api/java/util/zip/ZipFile.html#getName()
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