Given a non-negative number n and two values l and r. The problem is to unset the bits in the range l to r in the binary representation of n, i.e, to unset bits from the rightmost lth bit to the rightmost rth bit.
Constraint: 1 <= l <= r <= number of bits in the binary representation of n.
Examples:Â
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Input : n = 42, l = 2, r = 5 Output : 32 (42)10 = (101010)2 (32)10 = (100000)2 The bits in the range 2 to 5 in the binary representation of 42 have been unset. Input : n = 63, l = 1, r = 4 Output : 48
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Approach: Following are the steps:Â
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- Calculate num = (1 << (sizeof(int) * 8 – 1)) – 1. This will produce the highest positive integer num. All the bits in num will be set.
- Toggle bits in the range l to r in num. Refer this post.
- Now, perform n = n & num. This will unset the bits in the range l to r in n.
- Return n.
Note: The sizeof(int) has been used as input is of int data type. For large inputs you can use long int or long long int datatypes in place of int.Â
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C++
// C++ implementation to unset bits in the given range #include<bits/stdc++.h> using namespace std; Â
// Function to toggle bits in the given range int toggleBitsFromLToR( int n, int l, int r) {     // calculating a number 'num' having 'r' number of bits     // and bits in the range l to r are the only set bits     int num = ((1 << r) - 1) ^ ((1 << (l - 1)) - 1); Â
    // toggle the bits in the range l to r in 'n'     // and return the number     return (n ^ num); } Â
// Function to unset bits in the given range int unsetBitsInGivenRange( int n, int l, int r) {     // 'num' is the highest positive integer number     // all the bits of 'num' are set     long num = (1ll << (4 * 8 - 1)) - 1; Â
    // toggle the bits in the range l to r in 'num'     num = toggleBitsFromLToR(num, l, r); Â
    // unset the bits in the range l to r in 'n'     // and return the number     return (n & num); } Â
// driver program int main() { Â Â Â Â int n = 42; Â Â Â Â int l = 2, r = 5; Â Â Â Â cout<< unsetBitsInGivenRange(n, l, r); Â Â Â Â return 0; } |
Java
// Java implementation to unset bits in the given range import java.io.*; Â
class GFG {     // Function to toggle bits in the given range     static int toggleBitsFromLToR( int n, int l, int r)     {         // calculating a number 'num' having 'r' number of bits         // and bits in the range l to r are the only set bits         int num = (( 1 << r) - 1 ) ^ (( 1 << (l - 1 )) - 1 );           // toggle the bits in the range l to r in 'n'         // and return the number         return (n ^ num);     }          // Function to unset bits in the given range     static int unsetBitsInGivenRange( int n, int l, int r)     {         // 'num' is the highest positive integer number         // all the bits of 'num' are set         int num = ( 1 << ( 4 * 8 - 1 )) - 1 ;           // toggle the bits in the range l to r in 'num'         num = toggleBitsFromLToR(num, l, r);           // unset the bits in the range l to r in 'n'         // and return the number         return (n & num);     }          // driver program     public static void main (String[] args)     {         int n = 42 ;         int l = 2 , r = 5 ;         System.out.println(unsetBitsInGivenRange(n, l, r));     } } Â
// Contributed by Pramod Kumar |
Python3
# python implementation to unset bits # in the given range Â
# Function to toggle bits in the # given range def toggleBitsFromLToR(n, l, r):          # calculating a number 'num'     # having 'r' number of bits     # and bits in the range l to     # r are the only set bits     num = ((( 1 << r) - 1 ) ^            (( 1 << (l - 1 )) - 1 )) Â
    # toggle the bits in the range     # l to r in 'n' and return the     # number     return (n ^ num)      # Function to unset bits in the # given range def unsetBitsInGivenRange(n, l, r):          # 'num' is the highest positive     # integer number all the bits     # of 'num' are set     num = ( 1 << ( 4 * 8 - 1 )) - 1 Â
    # toggle the bits in the range     # l to r in 'num'     num = toggleBitsFromLToR(num, l, r) Â
    # unset the bits in the range     # l to r in 'n' and return the     # number     return (n & num) Â
# Driver code   n = 42 l = 2 r = 5 print (unsetBitsInGivenRange(n, l, r)) Â
# This code is contributed by Sam007. |
C#
// C# implementation to unset // bits in the given range using System;   class GFG {           // Function to toggle bits in the given range     static int toggleBitsFromLToR( int n, int l, int r)     {         // calculating a number 'num'         // having 'r' number of bits         // and bits in the range l         // to r are the only set bits         int num = ((1 << r) - 1) ^ ((1 << (l - 1)) - 1);           // toggle the bits in the         // range l to r in 'n'         // and return the number         return (n ^ num);     }           // Function to unset bits in the given range     static int unsetBitsInGivenRange( int n, int l, int r)     {         // 'num' is the highest         // positive integer number         // all the bits of 'num'         // are set         int num = (1 << (2 * 8 - 1)) - 1;           // toggle the bits in         // the range l to r in 'num'         num = toggleBitsFromLToR(num, l, r);           // unset the bits in         // the range l to r in 'n'         // and return the number         return (n & num);     }       // Driver Code static public void Main() {          int n = 42;     int l = 2, r = 5;     Console.WriteLine(unsetBitsInGivenRange(n, l, r)); } }   // This Code is Contributed by akt_mit |
PHP
<?php // PHP implementation to unset // bits in the given range Â
    // Function to toggle bits     // in the given range     function toggleBitsFromLToR( $n , $l , $r )     {                  // calculating a number 'num'         // having 'r' number of bits         // and bits in the range l to         // r are the only set bits         $num = ((1 << $r ) - 1) ^                ((1 << ( $l - 1)) - 1); Â
        // toggle the bits in the         // range l to r in 'n'         // and return the number         return ( $n ^ $num );     }          // Function to unset bits     // in the given range     function unsetBitsInGivenRange( $n , $l , $r )     {                  // 'num' is the highest         // positive integer number         // all the bits of 'num' are set         $num = (1 << (4 * 8 - 1)) - 1; Â
        // toggle the bits in the         // range l to r in 'num'         $num = toggleBitsFromLToR( $num , $l , $r ); Â
        // unset the bits in the         // range l to r in 'n'         // and return the number         return ( $n & $num );     }              // Driver Code         $n = 42;         $l = 2;         $r = 5;         echo unsetBitsInGivenRange( $n , $l , $r );      // This code is contributed by Sam007 ?> |
Javascript
<script>     // Javascript implementation to unset bits in the given range          // Function to toggle bits in the given range     function toggleBitsFromLToR(n, l, r)     {         // calculating a number 'num'         // having 'r' number of bits         // and bits in the range l         // to r are the only set bits         let num = ((1 << r) - 1) ^ ((1 << (l - 1)) - 1);             // toggle the bits in the         // range l to r in 'n'         // and return the number         return (n ^ num);     }             // Function to unset bits in the given range     function unsetBitsInGivenRange(n, l, r)     {         // 'num' is the highest         // positive integer number         // all the bits of 'num'         // are set         let num = (1 << (2 * 8 - 1)) - 1;             // toggle the bits in         // the range l to r in 'num'         num = toggleBitsFromLToR(num, l, r);             // unset the bits in         // the range l to r in 'n'         // and return the number         return (n & num);     }          let n = 42;     let l = 2, r = 5;     document.write(unsetBitsInGivenRange(n, l, r));      </script> |
Output:Â
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32
Time Complexity : O(1)
Auxiliary Space: O(1)
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