Sunday, October 12, 2025
HomeData Modelling & AIUnset bits in the given range

Unset bits in the given range

Given a non-negative number n and two values l and r. The problem is to unset the bits in the range l to r in the binary representation of n, i.e, to unset bits from the rightmost lth bit to the rightmost rth bit.
Constraint: 1 <= l <= r <= number of bits in the binary representation of n.
Examples: 
 

Input : n = 42, l = 2, r = 5
Output : 32
(42)10 = (101010)2
(32)10 = (100000)2
The bits in the range 2 to 5 in the binary
representation of 42 have been unset.

Input : n = 63, l = 1, r = 4
Output : 48

 

Approach: Following are the steps: 
 

  1. Calculate num = (1 << (sizeof(int) * 8 – 1)) – 1. This will produce the highest positive integer num. All the bits in num will be set.
  2. Toggle bits in the range l to r in num. Refer this post.
  3. Now, perform n = n & num. This will unset the bits in the range l to r in n.
  4. Return n.

Note: The sizeof(int) has been used as input is of int data type. For large inputs you can use long int or long long int datatypes in place of int. 
 

C++




// C++ implementation to unset bits in the given range
#include<bits/stdc++.h>
using namespace std;
 
// Function to toggle bits in the given range
int toggleBitsFromLToR(int n, int l, int r)
{
    // calculating a number 'num' having 'r' number of bits
    // and bits in the range l to r are the only set bits
    int num = ((1 << r) - 1) ^ ((1 << (l - 1)) - 1);
 
    // toggle the bits in the range l to r in 'n'
    // and return the number
    return (n ^ num);
}
 
// Function to unset bits in the given range
int unsetBitsInGivenRange(int n, int l, int r)
{
    // 'num' is the highest positive integer number
    // all the bits of 'num' are set
    long num = (1ll << (4 * 8 - 1)) - 1;
 
    // toggle the bits in the range l to r in 'num'
    num = toggleBitsFromLToR(num, l, r);
 
    // unset the bits in the range l to r in 'n'
    // and return the number
    return (n & num);
}
 
// driver program
int main()
{
    int n = 42;
    int l = 2, r = 5;
    cout<< unsetBitsInGivenRange(n, l, r);
    return 0;
}


Java




// Java implementation to unset bits in the given range
import java.io.*;
 
class GFG
{
    // Function to toggle bits in the given range
    static int toggleBitsFromLToR(int n, int l, int r)
    {
        // calculating a number 'num' having 'r' number of bits
        // and bits in the range l to r are the only set bits
        int num = ((1 << r) - 1) ^ ((1 << (l - 1)) - 1);
  
        // toggle the bits in the range l to r in 'n'
        // and return the number
        return (n ^ num);
    }
     
    // Function to unset bits in the given range
    static int unsetBitsInGivenRange(int n, int l, int r)
    {
        // 'num' is the highest positive integer number
        // all the bits of 'num' are set
        int num = (1 << (4 * 8 - 1)) - 1;
  
        // toggle the bits in the range l to r in 'num'
        num = toggleBitsFromLToR(num, l, r);
  
        // unset the bits in the range l to r in 'n'
        // and return the number
        return (n & num);
    }
     
    // driver program
    public static void main (String[] args)
    {
        int n = 42;
        int l = 2, r = 5;
        System.out.println(unsetBitsInGivenRange(n, l, r));
    }
}
 
// Contributed by Pramod Kumar


Python3




# python implementation to unset bits
# in the given range
 
# Function to toggle bits in the
# given range
def toggleBitsFromLToR(n, l, r):
     
    # calculating a number 'num'
    # having 'r' number of bits
    # and bits in the range l to
    # r are the only set bits
    num = (((1 << r) - 1) ^
           ((1 << (l - 1)) - 1))
 
    # toggle the bits in the range
    # l to r in 'n' and return the
    # number
    return (n ^ num)
     
# Function to unset bits in the
# given range
def unsetBitsInGivenRange(n, l, r):
     
    # 'num' is the highest positive
    # integer number all the bits
    # of 'num' are set
    num = (1 << (4 * 8 - 1)) - 1
 
    # toggle the bits in the range
    # l to r in 'num'
    num = toggleBitsFromLToR(num, l, r)
 
    # unset the bits in the range
    # l to r in 'n' and return the
    # number
    return (n & num)
 
# Driver code   
n = 42
l = 2
r = 5
print(unsetBitsInGivenRange(n, l, r))
 
# This code is contributed by Sam007.


C#




// C#  implementation to unset
// bits in the given range
using System;
  
class GFG {
      
    // Function to toggle bits in the given range
    static int toggleBitsFromLToR(int n, int l, int r)
    {
        // calculating a number 'num'
        // having 'r' number of bits
        // and bits in the range l
        // to r are the only set bits
        int num = ((1 << r) - 1) ^ ((1 << (l - 1)) - 1);
  
        // toggle the bits in the
        // range l to r in 'n'
        // and return the number
        return (n ^ num);
    }
      
    // Function to unset bits in the given range
    static int unsetBitsInGivenRange(int n, int l, int r)
    {
        // 'num' is the highest
        // positive integer number
        // all the bits of 'num'
        // are set
        int num = (1 << (2 * 8 - 1)) - 1;
  
        // toggle the bits in
        // the range l to r in 'num'
        num = toggleBitsFromLToR(num, l, r);
  
        // unset the bits in
        // the range l to r in 'n'
        // and return the number
        return (n & num);
    }
      
// Driver Code
static public void Main() {
     
    int n = 42;
    int l = 2, r = 5;
    Console.WriteLine(unsetBitsInGivenRange(n, l, r));
}
}
  
// This Code is  Contributed by akt_mit


PHP




<?php
// PHP implementation to unset
// bits in the given range
 
    // Function to toggle bits
    // in the given range
    function toggleBitsFromLToR($n, $l, $r)
    {
         
        // calculating a number 'num'
        // having 'r' number of bits
        // and bits in the range l to
        // r are the only set bits
        $num = ((1 << $r) - 1) ^
               ((1 << ($l - 1)) - 1);
 
        // toggle the bits in the
        // range l to r in 'n'
        // and return the number
        return ($n ^ $num);
    }
     
    // Function to unset bits
    // in the given range
    function unsetBitsInGivenRange($n,$l,$r)
    {
         
        // 'num' is the highest
        // positive integer number
        // all the bits of 'num' are set
        $num = (1 << (4 * 8 - 1)) - 1;
 
        // toggle the bits in the
        // range l to r in 'num'
        $num = toggleBitsFromLToR($num, $l, $r);
 
        // unset the bits in the
        // range l to r in 'n'
        // and return the number
        return ($n & $num);
    }
     
        // Driver Code
        $n = 42;
        $l = 2;
        $r = 5;
        echo unsetBitsInGivenRange($n, $l, $r);
     
// This code is contributed by Sam007
?>


Javascript




<script>
    // Javascript implementation to unset bits in the given range
     
    // Function to toggle bits in the given range
    function toggleBitsFromLToR(n, l, r)
    {
        // calculating a number 'num'
        // having 'r' number of bits
        // and bits in the range l
        // to r are the only set bits
        let num = ((1 << r) - 1) ^ ((1 << (l - 1)) - 1);
    
        // toggle the bits in the
        // range l to r in 'n'
        // and return the number
        return (n ^ num);
    }
        
    // Function to unset bits in the given range
    function unsetBitsInGivenRange(n, l, r)
    {
        // 'num' is the highest
        // positive integer number
        // all the bits of 'num'
        // are set
        let num = (1 << (2 * 8 - 1)) - 1;
    
        // toggle the bits in
        // the range l to r in 'num'
        num = toggleBitsFromLToR(num, l, r);
    
        // unset the bits in
        // the range l to r in 'n'
        // and return the number
        return (n & num);
    }
     
    let n = 42;
    let l = 2, r = 5;
    document.write(unsetBitsInGivenRange(n, l, r));
     
</script>


Output: 
 

32

Time Complexity : O(1)

Auxiliary Space: O(1)

This article is contributed by Ayush Jauhari. If you like neveropen and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the neveropen main page and help other Geeks.
Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
 

Feeling lost in the world of random DSA topics, wasting time without progress? It’s time for a change! Join our DSA course, where we’ll guide you on an exciting journey to master DSA efficiently and on schedule.
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 neveropen!

Dominic
Dominichttp://wardslaus.com
infosec,malicious & dos attacks generator, boot rom exploit philanthropist , wild hacker , game developer,
RELATED ARTICLES

Most Popular

Dominic
32352 POSTS0 COMMENTS
Milvus
87 POSTS0 COMMENTS
Nango Kala
6720 POSTS0 COMMENTS
Nicole Veronica
11885 POSTS0 COMMENTS
Nokonwaba Nkukhwana
11941 POSTS0 COMMENTS
Shaida Kate Naidoo
6840 POSTS0 COMMENTS
Ted Musemwa
7105 POSTS0 COMMENTS
Thapelo Manthata
6796 POSTS0 COMMENTS
Umr Jansen
6795 POSTS0 COMMENTS