Given a string S consisting of digits [0 – 9] and lowercase alphabets, the task is to calculate the sum of all numbers represented by continuous sequences of digits present in the string S.
Examples:
Input: S = “11aa32bbb5”
Output: 48
Explanation:
The consecutive sequence of numbers present in the string S are {11, 32, 5}.
Therefore, sum = 11 + 32 + 5 = 48Input: s = “5an63ff2”
Output: 70
Approach: Follow the steps below to solve the problem:
- Initialize a variable, say curr, to store the current sequence of consecutive digits
- Iterate over the characters of the string.
- If the current character is not a digit, add the current value of curr to the final answer. Reset curr to 0.
- Otherwise, append the current digit to curr.
- Finally, return the final answer.
Below is the implementation of the above approach:
C++
// C++ Program to implement// the above approach#include <bits/stdc++.h>using namespace std;// Function to calculate the sum of// numbers formed by consecutive// sequences of digits present in the stringint sumOfDigits(string s){ // Stores consecutive digits // present in the string int curr = 0; // Stores the sum int ret = 0; // Iterate over characters // of the input string for (auto& ch : s) { // If current character is a digit if (isdigit(ch)) { // Append current digit to curr curr = curr * 10 + ch - '0'; } else { // Add curr to sum ret += curr; // Reset curr curr = 0; } } ret += curr; return ret;}// Driver Codeint main(){ string S = "11aa32bbb5"; cout << sumOfDigits(S); return 0;} |
Java
// Java program to implement// the above approachimport java.io.*;import java.util.*;class GFG{ // Function to calculate the sum of // numbers formed by consecutive // sequences of digits present in the string static int sumOfDigits(String s) { // Stores consecutive digits // present in the string int curr = 0; // Stores the sum int ret = 0; // Iterate over characters // of the input string for(char ch : s.toCharArray()) { // If current character is a digit if (ch >= 48 && ch <= 57) { // Append current digit to curr curr = curr * 10 + ch - '0'; } else { // Add curr to sum ret += curr; // Reset curr curr = 0; } } ret += curr; return ret; } // Driver Code public static void main(String[] args) { String S = "11aa32bbb5"; System.out.print(sumOfDigits(S)); }}// This code is contributed by splevel62. |
Python3
# Python3 program for the above approach# Function to calculate the sum of# numbers formed by consecutive# sequences of digits present in the stringdef sumOfDigits(s) : # Stores consecutive digits # present in the string curr = 0 # Stores the sum ret = 0 # Iterate over characters # of the input string for ch in s : # If current character is a digit if (ord(ch) >= 48 and ord(ch) <= 57) : # Append current digit to curr curr = curr * 10 + ord(ch) - ord('0') else : # Add curr to sum ret += curr # Reset curr curr = 0 ret += curr return ret# Driver CodeS = "11aa32bbb5"print(sumOfDigits(S))# This code is contributed by code_hunt. |
C#
// C# Program to implement // the above approach using System;class GFG{ // Function to calculate the sum of // numbers formed by consecutive // sequences of digits present in the string static int sumOfDigits(string s) { // Stores consecutive digits // present in the string int curr = 0; // Stores the sum int ret = 0; // Iterate over characters // of the input string foreach(char ch in s) { // If current character is a digit if (ch >= 48 && ch <= 57) { // Append current digit to curr curr = curr * 10 + ch - '0'; } else { // Add curr to sum ret += curr; // Reset curr curr = 0; } } ret += curr; return ret; } // Driver code static void Main() { string S = "11aa32bbb5"; Console.WriteLine(sumOfDigits(S)); }}// This code is contributed by divyeshrabadiya07. |
Javascript
<script>// Javascript Program to implement// the above approach// Function to calculate the sum of// numbers formed by consecutive// sequences of digits present in the stringfunction sumOfDigits(s){ // Stores consecutive digits // present in the string var curr = 0; // Stores the sum var ret = 0; // Iterate over characters // of the input string s.split('').forEach(ch => { // If current character is a digit if (parseInt(ch)) { // Append current digit to curr curr = curr * 10 + ch.charCodeAt(0) - '0'.charCodeAt(0); } else { // Add curr to sum ret += curr; // Reset curr curr = 0; } }); ret += curr; return ret;}// Driver Codevar S = "11aa32bbb5";document.write( sumOfDigits(S));// This code is contributed by importantly.</script> |
Output:
48
Time Complexity: O(N)
Auxiliary Space: O(1)
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