Given an integer array 
, the task is to sort only the elements which are perfect squares at their relative positions in the array (positions of other elements must not be affected).
Examples:
Input: arr[] = {2, 64, 9, 8, 1, 4}
Output: 2 1 4 8 9 64
1, 4, 9 and 64 are the only perfect squares from the array.Input: arr[] = {1, 49, 2, 36}
Output: 1 36 2 49
Approach:
- Initialize two empty vectors and traverse the array from left to right.
- Take an integer and a float variable and for every element of the array store it’s square root in both of these variables.
- If both the variables are equal then push the index of this element in the first vector and push the element itself in the second vector.
- Sort the second vector.
- Now, we have the index of all the required elements in the first vector and also all of the required elements in sorted order in the second vector.
- So, insert the elements of the second vector into the array at the indices present in the first vector one by one.
Below is the implementation of the above approach:
C++
// C++ program to sort all the elements that are// perfect squares in their relative positions#include <bits/stdc++.h>using namespace std;// function to sort all the elements that are// perfect squares in their relative positionsvoid sortPerfectSquare(int arr[], int n){ int a; float b; // v1 will contain index of perfect squares // v2 will contain each perfect square vector<int> v1; vector<int> v2; for (int i = 0; i < n; i++) { b = sqrt(arr[i]); a = b; // if both a and b are equal then // arr[i] is a perfect square if (a == b) { v1.push_back(i); v2.push_back(arr[i]); } } // sort second vector sort(v2.begin(), v2.end()); // put the sorted perfect square // back into the array int j = 0; for (int i = 0; i < n; i++) { if (v1[j] == i) { arr[i] = v2[j]; j++; } } // print final array for (int i = 0; i < n; i++) cout << arr[i] << " ";}// Driver codeint main(){ int arr[] = { 9, 44, 100, 81, 21, 64 }; int n = sizeof(arr) / sizeof(arr[0]); sortPerfectSquare(arr, n); return 0;} |
Java
// Java program to sort all the elements that are // perfect squares in their relative positions import java.util.*;class GFG{// function to sort all the elements that are // perfect squares in their relative positions static void sortPerfectSquare(int arr[], int n) { int a; float b; // v1 will contain index of perfect squares // v2 will contain each perfect square Vector<Integer> v1 = new Vector<Integer>(); Vector<Integer> v2 = new Vector<Integer>(); for (int i = 0; i < n; i++) { b = (float) Math.sqrt(arr[i]); a = (int) b; // if both a and b are equal then // arr[i] is a perfect square if (a == b) { v1.add(i); v2.add(arr[i]); } } // sort second vector Collections.sort(v2); // put the sorted perfect square // back into the array int j = 0; for (int i = 0; i < n; i++) { if (v1.get(j) == i) { arr[i] = v2.get(j); j++; } } // print final array for (int i = 0; i < n; i++) System.out.print(arr[i]+" "); } // Driver code public static void main(String[] args) { int arr[] = { 9, 44, 100, 81, 21, 64 }; int n = arr.length; sortPerfectSquare(arr, n); }} // This code is contributed by 29AjayKumar |
Python3
# Python 3 program to sort all # the elements that are perfect # squares in their relative positions# import sqrt() from math libfrom math import sqrt# function to sort all the elements # that are perfect squares in their # relative positions def sortPerfectSquare(arr, n) : # v1 will contain index of # perfect squares and v2 will # contain each perfect square v1 = [] v2 = [] for i in range(n): b = sqrt(arr[i]) a = int(b) # if both a and b are equal then # arr[i] is a perfect square if a == b : v1.append(i) v2.append(arr[i]) # sort second list v2.sort() j = 0 # put the sorted perfect square # back into the array for i in range(n) : if v1[j] == i : arr[i] = v2[j] j += 1 # print final array for i in range(n) : print(arr[i], end = " ") # Driver codeif __name__ == "__main__" : arr = [9, 44, 100, 81, 21, 64] n = len(arr) sortPerfectSquare(arr, n); # This code is contributed by ANKITRAI1 |
C#
// C# program to sort all the elements that are // perfect squares in their relative positionsusing System;using System.Collections.Generic;class GFG{// function to sort all the elements that are // perfect squares in their relative positions static void sortPerfectSquare(int []arr, int n) { int a; float b; // v1 will contain index of perfect squares // v2 will contain each perfect square List<int> v1 = new List<int>(); List<int>v2 = new List<int>(); for (int i = 0; i < n; i++) { b = (float) Math.Sqrt(arr[i]); a = (int) b; // if both a and b are equal then // arr[i] is a perfect square if (a == b) { v1.Add(i); v2.Add(arr[i]); } } // sort second vector v2.Sort(); // put the sorted perfect square // back into the array int j = 0; for (int i = 0; i < n; i++) { if (v1[j] == i) { arr[i] = v2[j]; j++; } } // print final array for (int i = 0; i < n; i++) Console.Write(arr[i] + " "); } // Driver code public static void Main(String[] args){ int []arr = { 9, 44, 100, 81, 21, 64 }; int n = arr.Length; sortPerfectSquare(arr, n);}}// This code is contributed by// PrinciRaj1992 |
PHP
<?php// PHP program to sort all the elements that are// perfect squares in their relative positions// function to sort all the elements that are// perfect squares in their relative positionsfunction sortPerfectSquare($arr, $n){ // v1 will contain index of perfect squares // v2 will contain each perfect square $v1 = array(); $v2 = array(); for ( $i = 0; $i < $n; $i++) { $b = sqrt($arr[$i]); $a = (int)$b; // if both a and b are equal then // arr[i] is a perfect square if ($a == $b) { array_push($v1, $i); array_push($v2, $arr[$i]); } } // sort second vector sort($v2); // put the sorted perfect square // back into the array $j = 0; for ( $i = 0; $i < $n; $i++) { if ($v1[$j] == $i) { $arr[$i] = $v2[$j]; $j++; } } // print final array for ($i = 0; $i < $n; $i++) echo $arr[$i] . " ";}// Driver Code$arr = array( 9, 44, 100, 81, 21, 64 );$n = count($arr);sortPerfectSquare($arr, $n);// This code is contributed by Rajput-Ji?> |
Javascript
<script>// Javascript program to sort all the elements that are// perfect squares in their relative positions// function to sort all the elements that are// perfect squares in their relative positionsfunction sortPerfectSquare(arr, n){ var a; var b; // v1 will contain index of perfect squares // v2 will contain each perfect square var v1 = []; var v2 = []; for (var i = 0; i < n; i++) { b = Math.sqrt(arr[i]); a = parseInt(b); // if both a and b are equal then // arr[i] is a perfect square if (a == b) { v1.push(i); v2.push(arr[i]); } } // sort second vector v2.sort((a,b) => a-b) // put the sorted perfect square // back into the array var j = 0; for (var i = 0; i < n; i++) { if (v1[j] == i) { arr[i] = v2[j]; j++; } } // print final array for (var i = 0; i < n; i++) document.write( arr[i] + " ");}// Driver codevar arr = [9, 44, 100, 81, 21, 64 ];var n = arr.length;sortPerfectSquare(arr, n);</script> |
Output
9 44 64 81 21 100
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