Given an integer N ? 1, the task is to find the smallest N digit number which is a multiple of 5.
Examples:
Input: N = 1
Output: 5
Input: N = 2
Output: 10
Input: N = 3
Output: 100
Approach:
- If N = 1 then the answer will be 5.
- If N > 1 then the answer will be (10(N – 1)) because the series of smallest multiple of 5 will go on like 10, 100, 1000, 10000, 100000, …
Below is the implementation of the above approach:
C++
// C++ implementation of the approach #include <bits/stdc++.h> using namespace std; // Function to return the smallest n digit // number which is a multiple of 5 int smallestMultiple( int n) { if (n == 1) return 5; return pow (10, n - 1); } // Driver code int main() { int n = 4; cout << smallestMultiple(n); return 0; } |
Java
// Java implementation of the approach class GFG { // Function to return the smallest n digit // number which is a multiple of 5 static int smallestMultiple( int n) { if (n == 1 ) return 5 ; return ( int )(Math.pow( 10 , n - 1 )); } // Driver code public static void main(String args[]) { int n = 4 ; System.out.println(smallestMultiple(n)); } } |
Python3
# Python3 implementation of the approach # Function to return the smallest n digit # number which is a multiple of 5 def smallestMultiple(n): if (n = = 1 ): return 5 return pow ( 10 , n - 1 ) # Driver code n = 4 print (smallestMultiple(n)) |
C#
// C# implementation of the approach using System; class GFG { // Function to return the smallest n digit // number which is a multiple of 5 static int smallestMultiple( int n) { if (n == 1) return 5; return ( int )(Math.Pow(10, n - 1)); } // Driver code public static void Main() { int n = 4; Console.Write(smallestMultiple(n)); } } |
PHP
<?php // PHP implementation of the approach // Function to return the smallest n digit // number which is a multiple of 5 function smallestMultiple( $n ) { if ( $n == 1) return 5; return pow(10, $n - 1); } // Driver code $n = 4; echo smallestMultiple( $n ); ?> |
Javascript
<script> // Javascript implementation of the approach // Function to return the smallest n digit // number which is a multiple of 5 function smallestMultiple(n) { if (n == 1) return 5; return Math.pow(10, n - 1); } // Driver code var n = 4; document.write(smallestMultiple(n)); // This code is contributed by noob2000. </script> |
Output:
1000
Time Complexity: O(logn)
Auxiliary Space: O(1)
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