Given a number N, the task is to find the smallest Even number with N digits.
Examples:
Input: N = 1 Output: 0 Input: N = 2 Output: 10
Approach:
Case 1 : If N = 1 then answer will be 0.
Case 2 : if N != 1 then answer will be (10^(N-1)) because the series of smallest even numbers will go on like, 0, 10, 100, 1000, 10000, 100000, …..
Below is the implementation of the above approach:
C++
// C++ implementation of the approach#include <bits/stdc++.h>using namespace std;// Function to return smallest even// number with n digitsint smallestEven(int n){ if (n == 1) return 0; return pow(10, n - 1);}// Driver Codeint main(){ int n = 4; cout << smallestEven(n); return 0;} |
Java
// Java implementation of the approachclass Solution { // Function to return smallest even // number with n digits static int smallestEven(int n) { if (n == 1) return 0; return Math.pow(10, n - 1); } // Driver code public static void main(String args[]) { int n = 4; System.out.println(smallestEven(n)); }} |
Python3
# Python3 implementation of # the approach# Function to return smallest # even number with n digitsdef smallestEven(n) : if (n == 1): return 0 return pow(10, n - 1)# Driver Coden = 4print(smallestEven(n))# This code is contributed # by ihritik. |
C#
// C# implementation of the approachusing System;class Solution { // Function to return smallest even // number with n digits static int smallestEven(int n) { if (n == 1) return 0; return Math.pow(10, n - 1); } // Driver code public static void Main() { int n = 4; Console.Write(smallestEven(n)); }} |
PHP
<?php// PHP implementation of the approach// Function to return smallest // even number with n digitsfunction smallestEven($n){ if ($n == 1) return 0; return pow(10, $n - 1);}// Driver Code$n = 4;echo smallestEven($n);// This code is contributed // by ihritik.?> |
Javascript
<script>// Javascript implementation of the approach// Function to return smallest even// number with n digitsfunction smallestEven(n){ if (n == 1) return 0; return Math.pow(10, n - 1);}// Driver Codevar n = 4;document.write(smallestEven(n));// This code is contributed by rrrtnx.</script> |
1000
Time Complexity: O(log n).
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