Servlets are the Java programs that run on the Java-enabled web server or application server. They are used to handle the request obtained from the webserver, process the request, produce the response, then send a response back to the webserver.
Now let us learn how to upload a file to a server in this section. In an HTML file, the method must be posted and the enctype must be multipart/form-data when uploading a file to the server.
Creating a File Upload Form
- The following HTML code below creates an uploader form. The following are some key factors to remember:
- The form method should be set to POST, and the GET method should not be utilized.
- The multipart/form-data enctype property should be used.
- Set the form action property to a servlet file that will handle file uploading on the backend server. To upload a file, the following example uses the UploadServlet servlet.
- To upload a single file, use a single <input…/> element with the type=”file” attribute. Include several input tags with distinct names for the name attribute to allow various files to be uploaded. Each of them has a Browse button associated with it in the browser.
Implementation:
Step 1: We will create a dynamic web project in Eclipse and the project structure will look like the below image.
Remember: There are several options for uploading a file to the server. However, we are going to utilize O’Reilly’s MultipartRequest class. We will need the cos.jar file to use this class.
A. File: index.html
HTML
< html > < body > < form action = "GoGfg" method = "post" enctype = "multipart/form-data" > Select File:< input type = "file" name = "fname" />< br /> < input type = "submit" value = "upload" /> </ form > </ body > </ html > |
B. File: GfgFileUpload.java
Make sure you have created directories C:\\temp (it is with reference to Windows operating systems)
Example:
Java
// Java Program to Illustrate File Uploading // Via Servlets // Importing required classes import java.io.*; import javax.servlet.ServletException; import javax.servlet.http.*; import com.oreilly.servlet.MultipartRequest; // Class // Extending HttpServlet class public class GfgFileUpload extends HttpServlet { // Method // To handle request response mechanism public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { response.setContentType( "text/html" ); PrintWriter out = response.getWriter(); MultipartRequest m = new MultipartRequest(request, "C:\\temp" ); out.print( "File uploaded successfully" ); } } |
C. File: web.xml
XML
<? xml version = "1.0" encoding = "UTF-8" ?> < web-app > < servlet > < servlet-name >GfgFileUpload</ servlet-name > < servlet-class >GfgFileUpload</ servlet-class > </ servlet > < servlet-mapping > < servlet-name >GfgFileUpload</ servlet-name > < url-pattern >/GoGfg</ url-pattern > </ servlet-mapping > </ web-app > |
Output:
Step 2: After Clicking on the upload button file will be uploaded to the C:\\temp location