Given two dates (start date and end date) and the task is to return all the dates in an array.
Example 1: In this example, use date interval class which stores fixed amount of time (in years, months, days, hours etc) or relative time string in the format that DateTime.
<?php // Function to get all the dates in given range function getDatesFromRange($start, $end, $format = 'Y-m-d') { // Declare an empty array $array = array(); // Variable that store the date interval // of period 1 day $interval = new DateInterval('P1D'); $realEnd = new DateTime($end); $realEnd->add($interval); $period = new DatePeriod(new DateTime($start), $interval, $realEnd); // Use loop to store date into array foreach($period as $date) { $array[] = $date->format($format); } // Return the array elements return $array; } // Function call with passing the start date and end date $Date = getDatesFromRange('2010-10-01', '2010-10-05'); var_dump($Date); ?> |
Output:
array(5) {
[0]=>
string(10) "2010-10-01"
[1]=>
string(10) "2010-10-02"
[2]=>
string(10) "2010-10-03"
[3]=>
string(10) "2010-10-04"
[4]=>
string(10) "2010-10-05"
}
Example 2: This example use strtotime() function which is used to convert an English textual date-time description to a UNIX timestamp. It returns a timestamp on success, False otherwise.
<?php // Declare two dates $Date1 = '01-10-2010'; $Date2 = '05-10-2010'; // Declare an empty array $array = array(); // Use strtotime function $Variable1 = strtotime($Date1); $Variable2 = strtotime($Date2); // Use for loop to store dates into array // 86400 sec = 24 hrs = 60*60*24 = 1 day for ($currentDate = $Variable1; $currentDate <= $Variable2; $currentDate += (86400)) { $Store = date('Y-m-d', $currentDate); $array[] = $Store; } // Display the dates in array format print_r($array); ?> |
Output:
Array
(
[0] => 2010-10-01
[1] => 2010-10-02
[2] => 2010-10-03
[3] => 2010-10-04
[4] => 2010-10-05
)
