Given a string and List, replace each occurrence of K word in string with random element from list.
Input : test_str = “Gfg is x. Its also x for Lazyroar”, repl_list = [“Good”, “Better”, “Best”], repl_word = “x” Output : Gfg is Best. Its also Better for Lazyroar Explanation : x is replaced by random replace list values. Input : test_str = “Gfg is x. Its also x for Lazyroar”, repl_list = [“Good”, “Better”, “Nice”], repl_word = “x” Output : Gfg is Best. Its also Nice for Lazyroar Explanation : x is replaced by random replace list values, “Best” and “Nice”.
Method #1 : Using shuffle() + loop + replace()
The combination of above functions can be used to solve this problem. In this, we replace each occurrence of K word with random string from list using replace().
Python3
# Python3 code to demonstrate working of # Random Replacement of Word in String# Using replace() + shuffle() + loopfrom random import shuffle# initializing stringtest_str = "Gfg is val. Its also val for Lazyroar"# printing original stringprint("The original string is : " + str(test_str))# initializing list repl_list = ["Good", "Better", "Best"]# initializing replace wordrepl_word = "val"# shuffing list ordershuffle(repl_list)for ele in repl_list: # replacing with random string test_str = test_str.replace(repl_word, ele, 1) # printing result print("String after random replacement : " + str(test_str)) |
The original string is : Gfg is val. Its also val for Lazyroar String after random replacement : Gfg is Best. Its also Better for Lazyroar
Time Complexity: O(n*n) where n is the number of elements in the list “test_list”.
Auxiliary Space: O(n) where n is the number of elements in the list “test_list”.
Method #2 : Using list comprehension + replace() + shuffle()
This is one of the ways in which this task can be performed. In this, we encapsulate entire logic in one-liner using similar functionalities as above method.
Python3
# Python3 code to demonstrate working of # Random Replacement of Word in String# Using list comprehension + replace() + shuffle()from random import shuffle# initializing stringtest_str = "Gfg is val. Its also val for Lazyroar"# printing original stringprint("The original string is : " + str(test_str))# initializing list repl_list = ["Good", "Better", "Best"]# initializing replace wordrepl_word = "val"# one-liner to solve problemshuffle(repl_list)res = [test_str.replace(repl_word, ele, 1) for ele in repl_list] # printing result print("String after random replacement : " + str(res)) |
The original string is : Gfg is val. Its also val for Lazyroar String after random replacement : [‘Gfg is Good. Its also val for Lazyroar’, ‘Gfg is Better. Its also val for Lazyroar’, ‘Gfg is Best. Its also val for Lazyroar’]
The Time and Space Complexity for all the methods are the same:
Time Complexity: O(n)
Space Complexity: O(n)
