Given a tuple, the task is to write a Python program to delete the last element in the tuple in Python.
Example:
Input: (“Lazyroar”, “for”, “Lazyroar”)
Output:(“Lazyroar”, “for”)
Explanation: Here we are deleting the last element of the tuple and finally modifying the original one.
Note: Tuples are immutable datatypes i.e. they cannot be modified therefore other than slicing we cannot modify a tuple but what we can do is that we can convert a tuple into list and then perform operations according to our need.
Remove the last element from Tuple Using positive indexing
Python3
# create a tupletuple = ("Lazyroar", "for", "Lazyroar")# remove last elementl_element = len(tuple)-1tuple = tuple[:l_element]print(tuple) |
('Lazyroar', 'for')
Time Complexity: O(n)
Auxiliary Space: O(n), where n is length of tuple.
Explanation:
Here simply we find the index of the last element as (length of tuple-1) and then we update the current tuple with the modified or slicing tuple till the last element(excluding it).
Remove the last element from Tuple Using negative indexing
Python3
# create a tupletuple = ("Lazyroar", "for", "Lazyroar")# remove last elementtuple = tuple[:-1]print(tuple) |
('Lazyroar', 'for')
Explanation:
Here instead of finding the index of the last element we directly write -1( that denotes the last element in the iterable) and then simply slicing it till the last element and update the existing tuple.
Remove last element from Tuple Using lists
Python3
# create a listtu = (1, 2, 3, 4, 5)# remove last elementtu = list(tu)tu.pop(-1)tu = tuple(tu)print(tu) |
(1, 2, 3, 4)
Explanation:
As tuples are immutable we cannot directly modify them therefore first we convert it into lists then pop the last element.
Remove last element from Tuple Using lists remove() method
Python3
# create a listtu = (1, 2, 3, 4, 5)# remove last elementtu = list(tu)tu.remove(tu[-1])tu = tuple(tu)print(tu) |
(1, 2, 3, 4)
Remove last element from Tuple Using the filter() function.
Algorithm:
- Define a tuple “tu” containing the values (1, 2, 3, 4, 5).
- Use the filter function with a lambda function to remove the last element of the tuple. The lambda function checks
- whether the current element is not equal to the last element of the tuple.
- Convert the resulting filter object back to a tuple and store it in the variable “tu”.
- Print the updated tuple “tu”.
Python3
tu = (1, 2, 3, 4, 5)tu = tuple(filter(lambda x: x != tu[-1], tu))print(tu) |
(1, 2, 3, 4)
Time complexity:
The time complexity of this algorithm is O(n), where n is the length of the tuple “tu”. This is because the filter function and the tuple conversion both have a linear time complexity in the size of the input, and the lambda function is executed n times for a tuple of length n.
Auxiliary Space:
The space complexity of this algorithm is O(n), where n is the length of the tuple “tu”. This is because a new tuple is created to store the filtered elements, which requires memory proportional to the size of the input tuple.
