Given starting and endpoints, write a Python program to print all odd numbers in that given range.
Example:
Input: start = 4, end = 15 Output: 5, 7, 9, 11, 13, 15 Input: start = 3, end = 11 Output: 3, 5, 7, 9, 11
Example #1: Print all odd numbers from the given list using for loop
- Define the start and end limit of the range.
- Iterate from start till the range in the list using for loop and
- check if num % 2 != 0.
- If the condition satisfies, then only print the number.
Python3
# Python program to print odd Numbers in given rangestart, end = 4, 19# iterating each number in listfor num in range(start, end + 1): # checking condition if num % 2 != 0: print(num, end = " ") |
5 7 9 11 13 15 17 19
Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.
Example #2: Taking range limit from user input
Python3
# Python program to print Even Numbers in given rangestart = int(input("Enter the start of range:"))end = int(input("Enter the end of range:"))# iterating each number in listfor num in range(start, end + 1): # checking condition if num % 2 != 0: print(num) |
Output:
Enter the start of range: 3 Enter the end of range: 7 3 5 7
Time Complexity: O(N)
Auxiliary Space: O(1), As constant extra space is used.
Example #3: Taking range limit from user input or with static inputs to reduce code execution time and to increase code performance.
Python3
# Uncomment the below two lines for taking the User Inputs#start = int(input("Enter the start of range: "))#end = int(input("Enter the end of range: "))# Range declarationstart = 5end = 20if start % 2 != 0: for num in range(start, end + 1, 2): print(num, end=" ")else: for num in range(start+1, end + 1, 2): print(num, end=" ") |
5 7 9 11 13 15 17 19
Time Complexity: O(N), Here N is the difference of the end and start.
Auxiliary Space: O(1), As constant extra space is used.
Example #4: Taking range limit from user input
Python3
# Python program to print Even Numbers in given rangestart = int(input("Enter the start of range: "))end = int(input("Enter the end of range: "))#create a list that contains only Even numbers in given rangeeven_list = range(start, end + 1)[start%2::2]for num in even_list: print(num, end = " ") |
Enter the start of range: 3 Enter the end of range: 11 3 5 7 9 11
Time Complexity: O(n)
Auxiliary Space: O(n), As constant extra space is used.
Method: Using the lambda function
Python3
# Python code To print all odd numbers # in a given range using the lambda functiona=3;b=11li=[]for i in range(a,b+1): li.append(i)# printing odd numbers using the lambda functionodd_num = list(filter(lambda x: (x%2!=0),li)) print(odd_num) |
[3, 5, 7, 9, 11]
Time Complexity: O(n)
Auxiliary Space: O(1), As constant extra space is used.
Method: Using recursion
Python3
def odd(num1,num2): if num1>num2: return if num1&1: print(num1,end=" ") return odd(num1+2,num2) else: return odd(num1+1,num2)num1=5;num2=15odd(num1,num2) |
5 7 9 11 13 15
Time Complexity: O(n)
Auxiliary Space: O(1), As the function is tail recursive, no stack space is used.
Method: Using list comprehension
Python3
x = [i for i in range(4,15+1) if i%2!=0]print(*x) |
5 7 9 11 13 15
Time Complexity: O(n)
Auxiliary Space: O(1), As constant extra space is used.
Method: Using the enumerate function
Python3
a=4;b=15;l=[]for i in range(a,b+1): l.append(i)print([a for j,a in enumerate(l) if a%2!=0]) |
[5, 7, 9, 11, 13, 15]
Time Complexity: O(n)
Auxiliary Space: O(1), As constant extra space is used.
Method: Using pass
Python3
a=4;b=15for i in range(a,b+1): if i%2==0: pass else: print(i,end=" ") |
5 7 9 11 13 15
Time Complexity: O(n)
Auxiliary Space: O(1), As constant extra space is used.
Method: Using filter method:
Python3
# Python program to print Even Numbers in given range # Range declarationa=4;b=15;#create a list that contains only Even numbers in given rangel= filter(lambda a : a%2 , range(a, b+1))print(*l) |
5 7 9 11 13 15
Time Complexity: O(n)
Auxiliary Space: O(1), As constant extra space is used.
Method: Using bitwise & operator
Python3
# Python program to print odd Numbers in given range#using bitwise & operator start, end = 4, 19 # iterating each number in listfor num in range(start, end + 1): # checking condition if num & 1 != 0: print(num, end = " ") #this code is contributed by vinay pinjala. |
5 7 9 11 13 15 17 19
Time Complexity: O(n)
Auxiliary Space: O(1), As constant extra space is used.
Method: Using bitwise | operator
Python3
# Python program to print odd Numbers in given range#using bitwise | operator start, end = 4, 19 # iterating each number in listfor num in range(start, end + 1): # checking condition if num | 1 == num: print(num, end = " ") |
5 7 9 11 13 15 17 19
Time Complexity: O(n)
Auxiliary Space: O(1)
Method : Using numpy module:
Algorithm:
1.Input the range of numbers, a and b.
2.Import the NumPy library.
3.Create an array containing numbers in the range using np.arange(a, b+1).
4.Apply a boolean filter to select only the even numbers using arr[arr % 2 != 0].
5.Print the resulting array of even numbers using print(*evens).
Python3
import numpy as np# Range declarationa = 3b = 15# Create an array containing numbers in the rangearr = np.arange(a, b+1)# Create a new array containing only even numbersevens = arr[arr % 2 != 0]# Print the array of even numbersprint(*evens)#This code is contributed by Jyothi pinjala |
Output:
3 5 7 9 11 13 15
The time complexity :O(N), where N is the number of elements in the given range.
The auxiliary space :O(N), since it creates an array to hold all the numbers in the range, and then another array to hold only the even numbers.
Method: Using continue keyword
Approach:
- Define the start and end limit of the range.
- Iterate from start till the range in the list using for loop and
- Check the condition, if (i % 2) == 0.
- If condition satisfies, then skip the current iteration and increment the ith value.
- If condition doesn’t satisfies, then only print the number.
Python3
a = 4b = 15for i in range(a, b+1): if i % 2 == 0: continue else: print(i, end=" ") # This Code is contributed by Pratik Gupta (guptapratik) |
5 7 9 11 13 15
Time Complexity: O(n)
Auxiliary Space: O(1), as constant extra space is used.
Method: Using filterfalse method
Approach:
- Define the start and end limit of the range.
- Using filterfalse method in the range between start and end limit.
- filterfalse method checks the condition, x%2==0.
- Any number that satisfies the above condition is not a part of the result.
- The final result holds the number that is false in the above condition.
- print the final result.
Python3
# Python 3 code to demonstrate# print odd number in rangeimport itertools# Range declarationa = 3b = 15# using filterfalse function evens = list(itertools.filterfalse(lambda x: x%2==0, range(a, b+1)))# Print the array of even numbersprint(*evens) |
Output:
3 5 7 9 11 13 15
Time Complexity: O(N), Here N is the range between starting and ending limit.
Auxiliary Space: O(1), Because no extra space is used.
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