Given a dictionary with values as a list. Group all the keys together with similar values.
Input : test_dict = {“Gfg”: [5, 6], “is”: [8, 6, 9], “best”: [10, 9], “for”: [5, 2], “neveropen”: [19]}
Output : [[‘Gfg’, ‘is’, ‘for’], [‘is’, ‘Gfg’, ‘best’], [‘best’, ‘is’], [‘for’, ‘Gfg’]]
Explanation : Gfg has 6, is has 6, and for has 5 which is also in Gfg hence, grouped.Input : test_dict = {“Gfg”: [6], “is”: [8, 6, 9], “best”: [10, 9], “for”: [5, 2]}
Output : [[‘Gfg’, ‘is’], [‘is’, ‘Gfg’, ‘best’], [‘best’, ‘is’]]
Explanation : Gfg has 6, is has 6, hence grouped.
Method : Using loop + any() + len()
The combination of the above functions can be used to solve this problem. In this, we check for each key if it matches any value using any(), len() is used to check if the matching keys exceed 1. The iteration part is carried using a loop.
Python3
# Python3 code to demonstrate working of # Group keys with similar values in Dictionary# Using loop + any() + len()# initializing dictionarytest_dict = {"Gfg": [5, 6], "is": [8, 6, 9], "best": [10, 9], "for": [5, 2], "neveropen": [19]}# printing original dictionaryprint("The original dictionary is : " + str(test_dict))res = []for key in test_dict: chr = [key] for ele in test_dict: # check with other keys if key != ele: # checking for any match in values if any(i == j for i in test_dict[key] for j in test_dict[ele]): chr.append(ele) if len(chr) > 1: res.append(chr)# printing result print("The dictionary after values replacement : " + str(res)) |
Output:
The original dictionary is : {‘Gfg’: [5, 6], ‘is’: [8, 6, 9], ‘best’: [10, 9], ‘for’: [5, 2], ‘neveropen’: [19]}
The dictionary after values replacement : [[‘Gfg’, ‘is’, ‘for’], [‘is’, ‘Gfg’, ‘best’], [‘best’, ‘is’], [‘for’, ‘Gfg’]]
Time Complexity: O(n*n)
Auxiliary Space: O(n)
