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Python program to find files having a particular extension using RegEx

Prerequisite: Regular Expression in Python

Many of the times we need to search for a particular type of file from a list of different types of files. And we can do so with only a few lines of code using python. And the cool part is we don’t need to install any external package, python has a built-in package called re, with which we can easily write the program for performing this task.

Approach:

  • This program searches for the files having “.xml” extension from a list of different files.
  • Make a regular expression/pattern : “\.xml$”
  • Here re.search() function is used to check for a match anywhere in the string (name of the file). It basically returns the match object when the pattern is found and if the pattern is not found it returns null.
  • The functionality of different Metacharacters used here:
  1.  \  It is used to specify a special meaning of character after it. It is also used to escape special characters.
  2.  $ The string ends with the pattern which is before it.
  • Here “.xml” pattern is searched and processed.
  • Below is the implementation:

    Python3




    # import library
    import re
      
    # list of different types of file
    filenames = ["gfg.html", "Lazyroar.xml"
                "computer.txt", "neveropen.jpg"]
      
    for file in filenames:
        # search given pattern in the line 
        match = re.search("\.xml$", file)
      
        # if match is found
        if match:
            print("The file ending with .xml is:",
                 file)

    
    

    Output:

    The file ending with .xml is: Lazyroar.xml
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