Given a binary number, the task is to write a Python program to convert the given binary number into an equivalent hexadecimal number. i.e convert the number with base value 2 to base value 16. In hexadecimal representation we 16 values to represent a number. Numbers 0-9 are expressed by digits 0-9 and 10-15 are represented by characters from A – F.
Example:
Input: 1111 Output: F Input: 110101 Output: 35 Input: 100001111 Output: 10F
Method 1: User-defined Code To Convert Binary to Hexadecimal
Step 1: Input binary number.
Input: 111101111011
Step 2: Divide your binary number into groups of four, starting from right.
111101111011 = (1111)(0111)(1011)
Step 3: Convert one 4-digit group of a binary number to one hexadecimal digit.
(1111)(0111)(1011) = F7B
Below is the Python implementation of the above approach:
Python3
# Python code to convert binary number# into hexadecimal number# function to convert# binary to hexadecimaldef binToHexa(n): bnum = int(n) temp = 0 mul = 1 # counter to check group of 4 count = 1 # char array to store hexadecimal number hexaDeciNum = ['0'] * 100 # counter for hexadecimal number array i = 0 while bnum != 0: rem = bnum % 10 temp = temp + (rem*mul) # check if group of 4 completed if count % 4 == 0: # check if temp < 10 if temp < 10: hexaDeciNum[i] = chr(temp+48) else: hexaDeciNum[i] = chr(temp+55) mul = 1 temp = 0 count = 1 i = i+1 # group of 4 is not completed else: mul = mul*2 count = count+1 bnum = int(bnum/10) # check if at end the group of 4 is not # completed if count != 1: hexaDeciNum[i] = chr(temp+48) # check at end the group of 4 is completed if count == 1: i = i-1 # printing hexadecimal number # array in reverse order print("\n Hexadecimal equivalent of {}: ".format(n), end="") while i >= 0: print(end=hexaDeciNum[i]) i = i-1# Driver codeif __name__ == '__main__': binToHexa('1111') binToHexa('110101') binToHexa('100001111') binToHexa('111101111011') |
Output:
Hexadecimal equivalent of 1111: F Hexadecimal equivalent of 110101: 35 Hexadecimal equivalent of 100001111: 10F Hexadecimal equivalent of 111101111011: F7B
Method 2: First Convert Binary to Decimal and then Decimal to Hexadecimal
Step 1: Input binary number.
Input: 111101111011 = (111101111011)2
Step 2: Convert binary number to decimal number.
(111101111011)2 = (3963)10
Step 3: Convert the above decimal number to a hexadecimal number.
(3963)10 = (F7B)16
Below is the Python implementation of the above approach:
Python3
# Python program to convert binary number# into hexadecimal number# Function calculates the decimal equivalent# to given binary numberdef binaryToDecimal(binary): binary1 = int(binary) decimal, i, n = 0, 0, 0 while(binary1 != 0): dec = binary1 % 10 decimal = decimal + dec * pow(2, i) binary1 = binary1//10 i += 1 return(decimal)# function to convert# decimal to hexadecimaldef decToHexa(n): # char array to store # hexadecimal number hexaDeciNum = ['0'] * 100 # counter for hexadecimal # number array i = 0 while(n != 0): # temporary variable # to store remainder temp = 0 # storing remainder # in temp variable. temp = n % 16 # check if temp < 10 if(temp < 10): hexaDeciNum[i] = chr(temp + 48) i = i + 1 else: hexaDeciNum[i] = chr(temp + 55) i = i + 1 n = int(n / 16) # printing hexadecimal number # array in reverse order j = i - 1 while(j >= 0): print((hexaDeciNum[j]), end="") j = j - 1 print()# function to convert binary to# hexadecimaldef binToHexa(n): decimal = binaryToDecimal(n) print("Hexadecimal equivalent of {}: ".format(n)) decToHexa(decimal)# Driver codeif __name__ == '__main__': binToHexa('1111') binToHexa('110101') binToHexa('100001111') binToHexa('111101111011') |
Output:
Hexadecimal equivalent of 1111: F Hexadecimal equivalent of 110101: 35 Hexadecimal equivalent of 100001111: 10F Hexadecimal equivalent of 111101111011: F7B
Method 3: Using Predefined Functions
Example 1: Using int() and hex()
We use int() and hex() to convert a binary number to its equivalent hexadecimal number. Below is the Python implementation using int() and hex().
Python3
# Python code to convert from Binary# to Hexadecimal using int() and hex()def binToHexa(n): # convert binary to int num = int(n, 2) # convert int to hexadecimal hex_num = hex(num) return(hex_num)# Driver codeif __name__ == '__main__': print(binToHexa('1111')) print(binToHexa('110101')) print(binToHexa('100001111')) print(binToHexa('111101111011')) |
Output:
0xf 0x35 0x10f 0xf7b
Example 2: Using int() and format()
We use int() and format() to convert a binary number to its equivalent hexadecimal number. Below is the Python implementation using int() and format().
Python3
# Python code to convert from Binary# to hexadecimal using format()def binToHexa(n): # convert binary to int num = int(n, 2) # convert int to hexadecimal hex_num = format(num, 'x') return(hex_num)# Driver codeif __name__ == '__main__': print(binToHexa('1111')) print(binToHexa('110101')) print(binToHexa('100001111')) print(binToHexa('111101111011')) |
Output:
f 35 10f f7b
Time Complexity: O(logn)
Space Complexity: O(n)
