Given 2 lists, perform concatenations of all strings with each other across list.
Input : test_list1 = [“gfg”, “is”, “best”], test_list2 = [“love”, “CS”]
Output : [‘gfg love’, ‘gfg CS’, ‘is love’, ‘is CS’, ‘best love’, ‘best CS’]
Explanation : All strings are coupled with one another.Input : test_list1 = [“gfg”, “best”], test_list2 = [“love”, “CS”]
Output : [‘gfg love’, ‘gfg CS’, ‘best love’, ‘best CS’]
Explanation : All strings are coupled with one another.
Method #1: Using list comprehension
In this, we form pairs with each using list comprehension and then perform task of concatenation using another list comprehension.
Python3
# Python3 code to demonstrate working of # All elements concatenation across lists # Using list comprehension # initializing lists test_list1 = [ "gfg" , "is" , "best" ] test_list2 = [ "love" , "CS" ] # printing original lists print ( "The original list 1 is : " + str (test_list1)) print ( "The original list 2 is : " + str (test_list2)) # forming pairs temp = [(a, b) for a in test_list1 for b in test_list2] # performing concatenation res = [x + ' ' + y for (x, y) in temp] # printing result print ( "The paired combinations : " + str (res)) |
Output:
The original list 1 is : [‘gfg’, ‘is’, ‘best’] The original list 2 is : [‘love’, ‘CS’] The paired combinations : [‘gfg love’, ‘gfg CS’, ‘is love’, ‘is CS’, ‘best love’, ‘best CS’]
Time Complexity: O(n2) -> two for loops
Space Complexity: O(n)
Method #2 : Using product() + list comprehension
In this, we perform task of forming combination using product() and list comprehension performs the task of concatenation.
Python3
# Python3 code to demonstrate working of # All elements concatenation across lists # Using product() + list comprehension from itertools import product # initializing lists test_list1 = [ "gfg" , "is" , "best" ] test_list2 = [ "love" , "CS" ] # printing original lists print ( "The original list 1 is : " + str (test_list1)) print ( "The original list 2 is : " + str (test_list2)) # concatenation using formatting and pairing using product res = [ '%s %s' % (ele[ 0 ], ele[ 1 ]) for ele in product(test_list1, test_list2)] # printing result print ( "The paired combinations : " + str (res)) |
Output:
The original list 1 is : [‘gfg’, ‘is’, ‘best’] The original list 2 is : [‘love’, ‘CS’] The paired combinations : [‘gfg love’, ‘gfg CS’, ‘is love’, ‘is CS’, ‘best love’, ‘best CS’]
Time Complexity: O(n2) -> time complexity of product is O(n) and a for loop, O(n2)
Space Complexity: O(n)
Method #3: Using map and join
In this approach, we use map function to perform the task of concatenation and then join the resultant strings.
Python3
# Python3 code to demonstrate working of # All elements concatenation across lists # Using map() and join() from itertools import product # initializing lists test_list1 = [ "gfg" , "is" , "best" ] test_list2 = [ "love" , "CS" ] # printing original lists print ( "The original list 1 is : " + str (test_list1)) print ( "The original list 2 is : " + str (test_list2)) # concatenation using map() and join() res = list ( map ( ' ' .join, product(test_list1, test_list2))) # printing result print ( "The paired combinations : " + str (res)) |
The original list 1 is : ['gfg', 'is', 'best'] The original list 2 is : ['love', 'CS'] The paired combinations : ['gfg love', 'gfg CS', 'is love', 'is CS', 'best love', 'best CS']
Time Complexity: O(n2) -> time complexity of product is O(n) and a map function call O(n)
Auxiliary Space: O(n)
Method #4: Using itertools.product() and str.join()
- Import the itertools module, which provides various functions to work with iterators.
- Initialize two lists test_list1 and test_list2 with the desired elements.
- Use itertools.product() function to form all possible pairs of elements from test_list1 and test_list2. This function returns an iterator that generates the pairs one at a time.
- Store the iterator in a temporary variable called temp.
- Iterate over the temp iterator and for each pair, join the elements using a space separator (‘ ‘) and append the result to a list called res.
- Print the final result by converting the res list to a string using str() and passing it to the print() function
Python3
import itertools # initializing lists test_list1 = [ "gfg" , "is" , "best" ] test_list2 = [ "love" , "CS" ] # forming pairs temp = itertools.product(test_list1, test_list2) # performing concatenation res = [ ' ' .join(pair) for pair in temp] # printing result print ( "The paired combinations : " + str (res)) |
The paired combinations : ['gfg love', 'gfg CS', 'is love', 'is CS', 'best love', 'best CS']
Time complexity: O(n^2), where n is the length of the longer list (since we form all possible pairs).
Auxiliary space: O(n^2) for the temp list, since we need to store all the pairs.