Integers X and K are given. The task is to find smallest K-digit number divisible by X. Examples:
Input : X = 83, K = 5 Output : 10043 10040 is the smallest 5 digit number that is multiple of 83. Input : X = 5, K = 2 Output : 10
An efficient solution would be :
Compute MIN : smallest K-digit number (1000...K-times) If, MIN % X is 0, ans = MIN else, ans = (MIN + X) - ((MIN + X) % X)) This is because there will be a number in range [MIN...MIN+X] divisible by X.
Python3
# Python code to find smallest K-digit  # number divisible by X   def answer(X, K):           # Computing MAX     MIN = pow(10, K-1)           if(MIN%X == 0):         return (MIN)           else:         return ((MIN + X) - ((MIN + X) % X))         X = 83; K = 5;   print(answer(X, K));   # Code contributed by Mohit Gupta_OMG <(0_o)> |
Output :
10043
Time Complexity: O(logk)
Auxiliary Space: O(1)
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Please refer complete article on Smallest K digit number divisible by X for more details!
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