Math module in Python contains a number of mathematical operations, which can be performed with ease using the module.
math.isqrt() method in Python is used to get the integer square root of the given non-negative integer value n. This method returns the floor value of the exact square root of n or equivalently the greatest integer a such that a2 <= n.
Note: This method is new in Python version 3.8.
Syntax: math.isqrt(n)
Parameter:
n: A non-negative integerReturns: an integer value which represents the floor of exact square root of the given non-negative integer n.
Code #1: Use of math.isqrt() method
Python3
# Python Program to explain# math.isqrt() methodimport mathn = 10# Get the floor value of# exact square root of nsqrt = math.isqrt(n)print(sqrt)n = 100# Get the floor value of# exact square root of nsqrt = math.isqrt(n)print(sqrt) |
3 10
Code #2: Use of math.isqrt() method to check whether the given integer is a perfect square.
Python3
# Python Program to explain# math.isqrt() methodimport mathdef isPerfect(n): # Get the floor value of # exact square root of n sqrt = math.isqrt(n) if sqrt * sqrt == n: print(f"{n} is perfect square") else : print(f"{n} is not a perfect square")# Driver's codeisPerfect(100)isPerfect(10) |
100 is perfect square 10 is not a perfect square
Code #3: Use of math.isqrt() method to find the next perfect square of n.
Python3
# Python Program to explain# math.isqrt() methodimport mathn = 11def Next(n): # Get the ceiling of # exact square root of n ceil = 1 + math.isqrt(n) # print the next perfect square of n print("Next perfect square of {} is {}". format(n, ceil*ceil))# Driver's codeNext(11)Next(37) |
Next perfect square after 11 is 16 Next perfect square after 37 is 49
