Sometimes, while working with data, we can have a problem in which we need to get the Nth word of a String. This kind of problem has many application in school and day-day programming. Let’s discuss certain ways in which this problem can be solved.
Method #1 : Using loop This is one way in which this problem can be solved. In this, we run a loop and check for spaces. The Nth word is when there is N-1th space. We return that word.
Python3
# Python3 code to demonstrate working of# Get Nth word in String# using loop# initializing string test_str = "GFG is for Geeks"# printing original string print("The original string is : " + test_str)# initializing N N = 3# Get Nth word in String# using loopcount = 0res = ""for ele in test_str: if ele == ' ': count = count + 1 if count == N: break res = "" else : res = res + ele# printing resultprint("The Nth word in String : " + res) |
The original string is : GFG is for Geeks The Nth word in String : for
Method #2 : Using split() This is a shorthand with the help of which this problem can be solved. In this, we split the string into a list and then return the Nth occurring element.
Python3
# Python3 code to demonstrate working of# Get Nth word in String# using split()# initializing string test_str = "GFG is for Geeks"# printing original string print("The original string is : " + test_str)# initializing N N = 3# Get Nth word in String# using split()res = test_str.split(' ')[N-1]# printing resultprint("The Nth word in String : " + res) |
The original string is : GFG is for Geeks The Nth word in String : for
Method #3 : Using re.findall()
This approach uses the re.findall() function from the re library. It searches for all non-whitespace substrings in the given string and returns them in a list. The Nth word can then be accessed by indexing the list.
Python3
import re# initializing string test_str = "GFG is for Geeks" # printing original string print("The original string is : " + test_str) # initializing N N = 3 # Get Nth word in String# using re.findall()res = re.findall(r'\S+', test_str)# printing resultprint("The Nth word in String : " + res[N-1])#This code is contributed by Edula Vinay Kumar Reddy |
The original string is : GFG is for Geeks The Nth word in String : for
Time complexity is O(n) and Auxiliary Space is O(n).
Method 4 : using the string slicing method.
step-by-step approach
- Initialize the string.
- Print the original string.
- Initialize the value of N.
- Find the starting and ending indices of the Nth word using the string slicing method.
- Extract the Nth word using the starting and ending indices.
- Print the Nth word.
Python3
# initializing stringtest_str = "GFG is for Geeks"# printing original stringprint("The original string is : " + test_str)# initializing NN = 3# Get Nth word in String# using slicingstart = 0end = len(test_str)for i in range(N-1): start = test_str.find(" ", start) + 1for i in range(start, len(test_str)): if test_str[i] == " ": end = i breaknth_word = test_str[start:end]# printing resultprint("The Nth word in String : " + nth_word) |
The original string is : GFG is for Geeks The Nth word in String : for
Time Complexity: O(n), where n is the length of the given string.
Auxiliary Space: O(1)
