Given a quadratic equation, the task is to find the possible solutions to it.
Examples:
Input : enter the coef of x2 : 1 enter the coef of x : 2 enter the constant : 1 Output : the value for x is -1.0 Input : enter the coef of x2 : 2 enter the coef of x : 3 enter the constant : 2 Output : x1 = -3+5.656854249492381i/4 and x2 = -3-5.656854249492381i/4
Algorithm :
Start.
Prompt the values for a, b, c.
Compute i = b**2-4*a*c
If i get negative value g=square root(-i)
Else h = sqrt(i)
Compute e = -b+h/(2*a)
Compute f = -b-h/(2*a)
If condition e==f then
Print e
Else
Print e and f
If i is negative then
Print -b+g/(2*a) and -b-g/(2*a)
stop
Below is the Python implementation of the above mentioned task.
Python3
# Python program for solving a quadratic equation. from math import sqrt try: # if user gives non int values it will go to except block a = 1 b = 2 c = 1 i = b**2-4 * a * c # magic condition for complex values g = sqrt(-i) try: d = sqrt(i) # two resultants e = (-b + d) / 2 * a f = (-b-d) / 2 * a if e == f: print("the values for x is " + str(e)) else: print("the value for x1 is " + str(e) + " and x2 is " + str(f)) except ValueError: print("the result for your equation is in complex") # to print complex resultants. print("x1 = " + str(-b) + "+" + str(g) + "i/" + str(2 * a) + " and x2 = " + str(-b) + "-" + str(g) + "i/" + str(2 * a)) except ValueError: print("enter a number not a string or char") |
Output :
the values for x is -1.0
Explanation :
First, this program will get three inputs from the user. The values are the coefficient of 
, coefficient of 
and constant. Then it performs the formula 
For complex the value of 
gets negative. Rooting negative values will throw a value error. In this case, turn the result of 
and then root it. Don’t forget to include 
at last.
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