Given list of tuples, join consecutive tuples.
Input : test_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2)] Output : [(3, 5, 6, 7, 3, 2, 4, 3), (3, 2, 4, 3, 9, 4), (9, 4, 2, 3, 2)] Explanation : Elements joined with their consecutive tuples. Input : test_list = [(3, 5, 6, 7), (3, 2, 4, 3)] Output : [(3, 5, 6, 7, 3, 2, 4, 3)] Explanation : Elements joined with their consecutive tuples.
Method #1 : Using loop
This is brute way in which this task can be performed. In this, we perform task of joining consecution by access inside loop.
Python3
# Python3 code to demonstrate working of # Extend consecutive tuples# Using loop# initializing listtest_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2), (3, ), (3, 6)]# printing original listprint("The original list is : " + str(test_list))res = []for idx in range(len(test_list) - 1): # joining tuples res.append(test_list[idx] + test_list[idx + 1]) # printing resultsprint("Joined tuples : " + str(res)) |
The original list is : [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2), (3, ), (3, 6)] Joined tuples : [(3, 5, 6, 7, 3, 2, 4, 3), (3, 2, 4, 3, 9, 4), (9, 4, 2, 3, 2), (2, 3, 2, 3), (3, 3, 6)]
Time Complexity: O(n), where n is the length of the input list.
Auxiliary Space: O(n) additional space of size n is created where n is the number of elements in the list “test_list”.
Method #2 : Using zip() + list comprehension
In this, we construct consecutive list using zip() and slicing and then form pairs accordingly.
Python3
# Python3 code to demonstrate working of # Extend consecutive tuples# Using zip() + list comprehension# initializing listtest_list = [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2), (3, ), (3, 6)]# printing original listprint("The original list is : " + str(test_list))# zip to combine consecutive elements res = [a + b for a, b in zip(test_list, test_list[1:])] # printing resultsprint("Joined tuples : " + str(res)) |
The original list is : [(3, 5, 6, 7), (3, 2, 4, 3), (9, 4), (2, 3, 2), (3, ), (3, 6)] Joined tuples : [(3, 5, 6, 7, 3, 2, 4, 3), (3, 2, 4, 3, 9, 4), (9, 4, 2, 3, 2), (2, 3, 2, 3), (3, 3, 6)]
