Given dictionary list, extract dictionary with maximum keys.
Input : test_list = [{“gfg”: 2, “best” : 4}, {“gfg”: 2, “is” : 3, “best” : 4, “CS” : 9}, {“gfg”: 2}]
Output : 4
Explanation : 2nd dictionary has maximum keys, 4.Input : test_list = [{“gfg”: 2, “best” : 4}, {“gfg”: 2}]
Output : 2
Explanation : 1st dictionary has maximum keys, 2.
Method #1 : Using len() + loop
In this, we iterate for each of dictionary and compare lengths of each, record and return one with maximum length.
Python3
# Python3 code to demonstrate working of # Dictionary with maximum keys # Using loop + len() # initializing list test_list = [{"gfg": 2, "best" : 4}, {"gfg": 2, "is" : 3, "best" : 4}, {"gfg": 2}] # printing original list print("The original list is : " + str(test_list)) res = {} max_len = 0for ele in test_list: # checking for lengths if len(ele) > max_len: res = ele max_len = len(ele) # printing results print("Maximum keys Dictionary : " + str(res)) |
Output
The original list is : [{'gfg': 2, 'best': 4}, {'gfg': 2, 'is': 3, 'best': 4}, {'gfg': 2}]
Maximum keys Dictionary : {'gfg': 2, 'is': 3, 'best': 4}
Method #2 : Using max() + key=len
In this, we compute maximum length key using max() by passing additional key “len” for comparison based on lengths.
Python3
# Python3 code to demonstrate working of # Dictionary with maximum keys # Using max() + key = len # initializing list test_list = [{"gfg": 2, "best" : 4}, {"gfg": 2, "is" : 3, "best" : 4}, {"gfg": 2}] # printing original list print("The original list is : " + str(test_list)) # maximum length dict using len param res = max(test_list, key = len) # printing results print("Maximum keys Dictionary : " + str(res)) |
Output
The original list is : [{'gfg': 2, 'best': 4}, {'gfg': 2, 'is': 3, 'best': 4}, {'gfg': 2}]
Maximum keys Dictionary : {'gfg': 2, 'is': 3, 'best': 4}
