Given a series and a number N. The task is to find the Nth term of the given series:
3, 20, 63, 144, 230 …..
Examples:
Input: N = 4
Output: 144
When n = 4
nth term = 2 ( n * n * n ) + n * n
= 2 ( 4 * 4 * 4 ) + 4 * 4
= 144
Input: N = 10
Output: 2100
Approach: We can find the general term (Tn) of the given series. 
Below is the required implementation:
C++
// CPP program to find N-th term of the series:// 3, 20, 63, 144, 230 .....#include <iostream>#include <math.h>using namespace std;// calculate Nth term of seriesint nthTerm(int n){ return 2 * pow(n, 3) + pow(n, 2);}// Driver codeint main(){ int N = 3; cout << nthTerm(N); return 0;} |
Java
// Java program to find N-th term of the series:// 3, 20, 63, 144, 230 .....import java.util.*;class solution{// calculate Nth term of seriesstatic int nthTerm(int n){ //return final sum return 2 *(int)Math.pow(n, 3) + (int)Math.pow(n, 2);}// Driver codepublic static void main(String arr[]){ int N = 3;System.out.println(nthTerm(N));}}//This code is contributed by Surendra_Gangwar |
Python 3
# Python program to find# N-th term of the series: # 3, 20, 63, 144, 230 .....# calculate Nth term of series def nthTerm(n) : return 2 * pow(n, 3) + pow(n, 2)# Driver codeif __name__ == "__main__" : N = 3 print(nthTerm(N))# This code is contributed # by ANKITRAI1 |
C#
// C# program to find N-th term of the series:// 3, 20, 63, 144, 230 .....using System;class solution{// calculate Nth term of seriesstatic int nthTerm(int n){ //return final sum return 2 *(int)Math.Pow(n, 3) + (int)Math.Pow(n, 2);}// Driver codepublic static void Main(){ int N = 3;Console.WriteLine(nthTerm(N));}}//This code is contributed by Shashank |
PHP
<?php// PHP program to find // N-th term of the series:// 3, 20, 63, 144, 230 .....// calculate Nth term of seriesfunction nthTerm($n){ return 2 * pow($n, 3) + pow($n, 2);}// Driver code$N = 3;echo nthTerm($N);//This code is contributed by Shashank?> |
Javascript
<script>// JavaScript program to find N-th term of the series:// 3, 20, 63, 144, 230 .....// calculate Nth term of seriesfunction nthTerm( n){ return 2 * Math.pow(n, 3) + Math.pow(n, 2);}// Driver code let N = 3; document.write( nthTerm(N) );// This code contributed by aashish1995 </script> |
Output:
63
Time Complexity: O(1), since there is no loop or recursion.
Auxiliary Space: O(1) since using constant variables
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