Given a number N. The task is to write a program to find the Nth term of the below series:
0, 14, 40, 78, 124 …(N Terms)
Examples:
Input: N = 4
Output: 78
For N = 4
Sum(upto 4 terms) = ( 6 * n * n - 4 * n - 2)
= ( 6 * 4 * 4 - 4 * 4 - 2)
= 78
Input: N = 10
Output: 557
Approach: The generalized Nth term of this series:
Below is the required implementation:
C++
// CPP program to find the N-th term of the series// 0, 14, 40, 78, 124 ...#include <iostream>#include <math.h>using namespace std;// calculate sum upto Nth term of seriesint nthTerm(int n){ return 6 * pow(n, 2) - 4 * n - 2;}// Driver codeint main(){ int N = 4; cout << nthTerm(N); return 0;} |
Java
// Java program to find the N-th term of the series// 0, 14, 40, 78, 124 ...import java.util.*;class solution{// calculate sum up to Nth term of seriesstatic int nthTerm(int n){ //return the final sum return 6 * (int)Math.pow(n, 2) - 4 * n - 2;}// Driver codepublic static void main(String arr[]){ int N = 4; System.out.println(nthTerm(N));}}//This code is contributed by Surendra_Gangwar |
Python3
# Python3 program to find # the N-th term of the series# 0, 14, 40, 78, 124 ...# calculate sum upto Nth # term of seriesdef nthTerm(n): return int(6 * pow(n, 2) - 4 * n - 2)# Driver codeN = 4print(nthTerm(N))# This code is contributed # by Shrikant13 |
C#
// C# program to find the // N-th term of the series// 0, 14, 40, 78, 124 ...using System;class GFG{// calculate sum up to Nth // term of seriesstatic int nthTerm(int n){ //return the final sum return 6 * (int)Math.Pow(n, 2) - 4 * n - 2;}// Driver codepublic static void Main(){ int N = 4; Console.WriteLine(nthTerm(N));}}// This code is contributed // by inder_verma |
PHP
<?php// PHP program to find the// N-th term of the series// 0, 14, 40, 78, 124 ...// calculate sum upto // Nth term of seriesfunction nthTerm($n){ return 6 * pow($n, 2) - 4 * $n - 2;}// Driver code$N = 4;echo nthTerm($N);// This code is contributed by // Akanksha Rai(Abby_akku) |
Javascript
<script>// JavaScript program to find the N-th term of the series// 0, 14, 40, 78, 124 ...// calculate sum upto Nth term of seriesfunction nthTerm( n){ return 6 * Math.pow(n, 2) - 4 * n - 2;}// Driver code let N = 4; document.write( nthTerm(N) );// This code contributed by aashish1995</script> |
Output:
78
Time Complexity: O(logN) because using inbuilt pow function
Space Complexity: O(1) since using constant variables
Note: Sum upto n terms of the above series(Sn) is: 
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