The value of any article or item subject to wear and tear, decreases with time. This decrease is called its Depreciation. Given three variable V1, R and T where V1 is the initial value, R is the rate of depreciation and T is the time in years. The task is to find the value of the item after T years.
Examples:
Input: V1 = 200, R = 10, T = 2
Output: 162
Input: V1 = 560, R = 5, T = 3
Output: 480.13
Approach: As in Compound Interest, interest is regularly added to the principal at the end of the agreed intervals of time to generate a new and fresh principal. Similarly, Depreciated value is the decreased value from the amount at the end of agreed intervals of time to generate a new Value.
Thus if V1 is the value at a certain time and R% per annum is the rate (the rate can not be more than 100%) of depreciation per year, then the value V2 at the end of T years is:
Below is the implementation of the above approach :
C++
// CPP program to find depreciation of the value// initial value, rate and time are given#include <bits/stdc++.h>using namespace std;// Function to return the depreciation of valuefloat Depreciation(float v, float r, float t){ float D = v * pow((1 - r / 100), t); return D;}// Driver Codeint main(){ float V1 = 200, R = 10, T = 2; cout << Depreciation(V1, R, T); return 0;} |
Java
// Java program to find depreciation of the value// initial value, rate and time are givenimport java.io.*;class GFG{// Function to return the depreciation of valuestatic float Depreciation(float v, float r, float t){ float D = (float)(v * Math.pow((1 - r / 100), t)); return D;}// Driver code public static void main(String[] args){ float V1 = 200, R = 10, T = 2; System.out.print(Depreciation(V1, R, T)); } }// This code is contributed by anuj_67.. |
Python3
# Python 3 program to find depreciation of the value# initial value, rate and time are givenfrom math import pow# Function to return the depreciation of valuedef Depreciation(v, r, t): D = v * pow((1 - r / 100), t) return D# Driver Codeif __name__ == '__main__': V1 = 200 R = 10 T = 2 print(int(Depreciation(V1, R, T)))# This code is contributed by# Surendra_Gangwar |
C#
// C# program to find depreciation of the value// initial value, rate and time are givenusing System;class GFG{// Function to return the depreciation of valuestatic float Depreciation(float v, float r, float t){ float D = (float) (v * Math.Pow((1 - r / 100), t)); return D;}// Driver code public static void Main(){ float V1 = 200, R = 10, T = 2; Console.WriteLine(Depreciation(V1, R, T)); } }// This code is contributed by nidhiva |
Javascript
// javascript program to find depreciation of the value// initial value, rate and time are given// Function to return the depreciation of value function Depreciation( v, r, t){ var D = v * Math.pow((1 - r / 100), t) return D;} // Driver code var V1 = 200, R = 10, T = 2; document.write(Depreciation(V1, R, T)); // This code is contributed by bunnyram19. |
162
Time Complexity: O(1)
Auxiliary Space: O(1)
Ready to dive in? Explore our Free Demo Content and join our DSA course, trusted by over 100,000 neveropen!
