Given a number N. The task is to write a program to find the Nth term of the below series:
0, 9, 22, 39, 60, 85, 114, 147…..(N Terms)
Examples:
Input: N = 4
Output: 39
For N = 4
4th Term = ( 2 * 4 * 4 + 3 * 4 - 5)
= 39
Input: N = 10
Output: 224
Approach: The generalized Nth term of this series:
Below is the required implementation:
C++
// C++ program to find the N-th term of the series:// 0, 9, 22, 39, 60, 85, 114, 147.....#include <iostream>#include <math.h>using namespace std;// calculate Nth term of seriesint nthTerm(int n){ return 2 * pow(n, 2) + 3 * n - 5;}// Driver codeint main(){ int N = 4; cout << nthTerm(N) << endl; return 0;} |
Java
// Java program to find the N-th term of the series: // 0, 9, 22, 39, 60, 85, 114, 147..... public class GFG { // calculate Nth term of series static int nthTerm(int n) { return 2 * (int)Math.pow(n, 2) + 3 * n - 5; } // Driver code public static void main(String args[]) { int N = 4; System.out.println(nthTerm(N)); } // This Code is contributed by ANKITRAI1} |
Python3
# Python3 program to find the# N-th term of the series:# 0, 9, 22, 39, 60, 85, 114, 147.....# calculate Nth term of seriesdef nthTerm(n): return 2 * pow(n, 2) + 3 * n - 5# Driver codeN = 4print(nthTerm(N))# This code is contributed by# Sanjit_Prasad |
C#
// C# program to find the// N-th term of the series: // 0, 9, 22, 39, 60, 85, 114, 147..... using System;class GFG{// calculate Nth term of series static int nthTerm(int n) { return 2 * (int)Math.Pow(n, 2) + 3 * n - 5; } // Driver codepublic static void Main(){ int N = 4; Console.WriteLine(nthTerm(N)); }}// This Code is contributed// by Akanksha Rai(Abby_akku) |
PHP
<?php // PHP program to find the // N-th term of the series:// 0, 9, 22, 39, 60, 85, 114, 147.....// calculate Nth term of seriesfunction nthTerm($n){ return 2 * pow($n, 2) + 3 * $n - 5;}// Driver code$N = 4;echo nthTerm($N)."\n";// This code is contributed// by ChitraNayal?> |
Javascript
<script>// JavaScript program to find the N-th term of the series:// 0, 9, 22, 39, 60, 85, 114, 147.....// calculate Nth term of seriesfunction nthTerm( n){ return 2 * Math.pow(n, 2) + 3 * n - 5;}// Driver code let N = 4; document.write(nthTerm(N));// This code contributed by gauravrajput1 </script> |
Output:
39
Time Complexity: O(1), since there is no loop or recursion.
Space Complexity: O(1) since using constant variables
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