Given a complex number in the form of the string str, the task is to determine the quadrant of the cartesian plane in which this complex number lies.
Examples:
Input: str = “1 + 1i”
Output: Quadrant 1Input: str = “0 + 0i”
Output: Origin
Approach:
The idea is to first find the real and imaginary parts of a complex number. Let’s say the point is (x, iy), then the following table illustrates the position of the point with respect to the coordinates:
Below is the implementation of the above approach:
C++
// C++ program to determine the quadrant// of a complex number#include <bits/stdc++.h>using namespace std;// Function to determine the quadrant// of a complex numbervoid quadrant(string s){ int l = s.length(); int i; // Storing the index of '+' if (s.find('+') < l) { i = s.find('+'); } // Storing the index of '-' else { i = s.find('-'); } // Finding the real part // of the complex number string real = s.substr(0, i); // Finding the imaginary part // of the complex number string imaginary = s.substr(i + 1, l - 1); int x = stoi(real); int y = stoi(imaginary); if (x > 0 and y > 0) cout << "Quadrant 1"; else if (x < 0 and y > 0) cout << "Quadrant 2"; else if (x < 0 and y < 0) cout << "Quadrant 3"; else if (x > 0 and y < 0) cout << "Quadrant 4"; else if (x == 0 and y > 0) cout << "Lies on positive" << " Imaginary axis"; else if (x == 0 and y < 0) cout << "Lies on negative" << " Imaginary axis"; else if (y == 0 and x < 0) cout << "Lies on negative" << " X-axis"; else if (y == 0 and x > 0) cout << "Lies on positive" << " X-axis"; else cout << "Lies on the Origin";}// Driver codeint main(){ string s = "5+3i"; quadrant(s); return 0;} |
Java
// Java program to determine the quadrant// of a complex numberimport java.util.*;class GFG{ // Function to determine the quadrant// of a complex numberstatic void quadrant(String s){ int l = s.length(); int i; // Storing the index of '+' if (s.contains("+")) { i = s.indexOf('+'); } // Storing the index of '-' else { i = s.indexOf('-'); } // Finding the real part // of the complex number String real = s.substring(0, i); // Finding the imaginary part // of the complex number String imaginary = s.substring(i + 1, l - 1); int x = Integer.valueOf(real); int y = Integer.valueOf(imaginary); if (x > 0 && y > 0) System.out.print("Quadrant 1"); else if (x < 0 && y > 0) System.out.print("Quadrant 2"); else if (x < 0 && y < 0) System.out.print("Quadrant 3"); else if (x > 0 && y < 0) System.out.print("Quadrant 4"); else if (x == 0 && y > 0) System.out.print("Lies on positive" + " Imaginary axis"); else if (x == 0 && y < 0) System.out.print("Lies on negative" + " Imaginary axis"); else if (y == 0 && x < 0) System.out.print("Lies on negative" + " X-axis"); else if (y == 0 && x > 0) System.out.print("Lies on positive" + " X-axis"); else System.out.print("Lies on the Origin");} // Driver codepublic static void main(String[] args){ String s = "5+3i"; quadrant(s);}}// This code is contributed by Rajput-Ji |
Python3
# Python 3 program to determine the quadrant# of a complex number# Function to determine the quadrant# of a complex numberdef quadrant(s): l = len(s) # Storing the index of '+' if ('+' in s): i = s.index('+') # Storing the index of '-' else: i = s.index('-') # Finding the real part # of the complex number real = s[0:i] # Finding the imaginary part # of the complex number imaginary = s[i + 1:l - 1] x = int(real) y = int(imaginary) if (x > 0 and y > 0): print("Quadrant 1") elif(x < 0 and y > 0): print("Quadrant 2") elif (x < 0 and y < 0): print("Quadrant 3") elif (x > 0 and y < 0): print("Quadrant 4") elif (x == 0 and y > 0): print("Lies on positive","Imaginary axis") elif (x == 0 and y < 0): print("Lies on negative","Imaginary axis") elif (y == 0 and x < 0): print("Lies on negative","X-axis") elif (y == 0 and x > 0): print("Lies on positive","X-axis") else: print("Lies on the Origin")# Driver codeif __name__ == '__main__': s = "5+3i" quadrant(s) # This code is contributed by Surendra_Gangwar |
C#
// C# program to determine the quadrant// of a complex numberusing System;class GFG{ // Function to determine the quadrant// of a complex numberstatic void quadrant(String s){ int l = s.Length; int i; // Storing the index of '+' if (s.Contains("+")) { i = s.IndexOf('+'); } // Storing the index of '-' else { i = s.IndexOf('-'); } // Finding the real part // of the complex number String real = s.Substring(0, i); // Finding the imaginary part // of the complex number String imaginary = s.Substring(i + 1, l - 2 - i); int x = Int32.Parse(real); int y = Int32.Parse(imaginary); if (x > 0 && y > 0) Console.Write("Quadrant 1"); else if (x < 0 && y > 0) Console.Write("Quadrant 2"); else if (x < 0 && y < 0) Console.Write("Quadrant 3"); else if (x > 0 && y < 0) Console.Write("Quadrant 4"); else if (x == 0 && y > 0) Console.Write("Lies on positive" + " Imaginary axis"); else if (x == 0 && y < 0) Console.Write("Lies on negative" + " Imaginary axis"); else if (y == 0 && x < 0) Console.Write("Lies on negative" + " X-axis"); else if (y == 0 && x > 0) Console.Write("Lies on positive" + " X-axis"); else Console.Write("Lies on the Origin");} // Driver codepublic static void Main(String[] args){ String s = "5+3i"; quadrant(s);}} // This code is contributed by sapnasingh4991 |
Javascript
<script>// Javascript program// Function to determine the quadrant// of a complex numberfunction quadrant(s){ var l = s.length; var i =0 ; // Storing the index of '+' if (s.indexOf("+") != -1) { i = s.indexOf("+"); } // Storing the index of '-' else { i = s.indexOf("-"); } // Finding the real part // of the complex number var real = s.substr(0, i); // Finding the imaginary part // of the complex number var imaginary = s.substr(i + 1, l - 1); var x = parseInt(real); var y = parseInt(imaginary); if (x > 0 && y > 0) document.write("Quadrant 1"); else if (x < 0 && y > 0) document.write("Quadrant 2"); else if (x < 0 && y < 0) document.write( "Quadrant 3"); else if (x > 0 && y < 0) document.write( "Quadrant 4"); else if (x == 0 && y > 0) document.write( "Lies on positive"+" Imaginary axis"); else if (x == 0 && y < 0) document.write( "Lies on negative"+" Imaginary axis"); else if (y == 0 && x < 0) document.write( "Lies on negative"+" X-axis"); else if (y == 0 && x > 0) document.write( "Lies on positive"+" X-axis"); else document.write( "Lies on the Origin");} var s = "5+3i";quadrant(s);</script> |
Output:
Quadrant 1
Time complexity: O(n) where n is the size of the given string
Auxiliary space: O(n) because extra space for string real and imaginary is being used
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