Given a positive integer S, the task is to find the length of diagonal of a square having sides of length S.
Examples:
Input: S = 10
Output: 14.1421
Explanation: The length of the diagonal of a square whose sides are of length 10 is 14.1421Input: S = 24
Output: 33.9411
Approach: The given problem can be solved based on the mathematical relation between the length of sides of a square and the length of diagonal of a square as illustrated below:
As visible from the above image, the diagonal and the two sides of the square form a right-angled triangle. Therefore, by applying Pythagoras Theorem:
(hypotenuse)2 = (base)2 + (perpendicular)2, where D and S are length of the diagonal and the square.Therefore,
=>
=>
=>
Therefore, simply calculate the length of the diagonal using the above-derived relation.
Below is the implementation of the above approach:
C++
// C++ program for the above approach #include <bits/stdc++.h> using namespace std; // Function to find the length of the // diagonal of a square of a given side double findDiagonal( double s) { return sqrt (2) * s; } // Driver Code int main() { double S = 10; cout << findDiagonal(S); return 0; } |
Java
// Java program for the above approach import java.util.*; class GFG{ // Function to find the length of the // diagonal of a square of a given side static double findDiagonal( double s) { return ( double )Math.sqrt( 2 ) * s; } // Driver Code public static void main(String[] args) { double S = 10 ; System.out.print(findDiagonal(S)); } } // This code is contributed by splevel62 |
Python3
# Python3 program for the above approach import math # Function to find the length of the # diagonal of a square of a given side def findDiagonal(s): return math.sqrt( 2 ) * s # Driver Code if __name__ = = "__main__" : S = 10 print (findDiagonal(S)) # This code is contributed by chitranayal |
C#
// C# program for the above approach using System; public class GFG { // Function to find the length of the // diagonal of a square of a given side static double findDiagonal( double s) { return ( double )Math.Sqrt(2) * s; } // Driver Code public static void Main(String[] args) { double S = 10; Console.Write(findDiagonal(S)); } } // This code is contributed by 29AjayKumar |
Javascript
<script> // JavaScript program for the above approach // Function to find the length of the // diagonal of a square of a given side function findDiagonal(s) { return Math.sqrt(2) * s; } // Driver Code var S = 10; document.write(findDiagonal(S).toFixed(6)); // This code contributed by shikhasingrajput </script> |
14.1421
Time Complexity: O(1)
Auxiliary Space: O(1)
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