Given an array of size n and the task is to find Coefficient of variation . Coefficient of variation is the ratio of standard deviation and mean. The main purpose of coefficient of variation is to find study of quality assurance by measuring the dispersion of the population data of a probability or frequency distribution, or by determining the content or quality of the sample data of substances. The method of measuring the ratio of standard deviation to mean is also known as relative standard deviation often abbreviated as RSD.
Examples :
Input : arr[] = {60.25, 62.38, 65.32, 61.41, 63.23}
Output : 0.0307144
Input : arr[] = {15, 36, 53.67, 25.45, 67.8, 56, 78.09}
Output : 0.48177
Approach:
Coefficient of Variation = Standard deviation / mean Example: arr[] = {60.25, 62.38, 65.32, 61.41, 63.23} mean = 62.518 Standard Deviation = 1.9202 Coefficient of Variation = Standard deviation / mean = 1.9202 / 62.518 = 0.0307144
Below is the implementation of the above formula :
C++
// Program to find coefficient of // variation of given array.#include <bits/stdc++.h>using namespace std;// Function to find mean of given array.float mean(float arr[], int n){ float sum = 0; for (int i = 0; i < n; i++) sum = sum + arr[i]; return sum / n;}// Function to find standard deviation // of given array.float standardDeviation(float arr[], int n){ float sum = 0; for (int i = 0; i < n; i++) sum = sum + (arr[i] - mean(arr, n)) * (arr[i] - mean(arr, n)); return sqrt(sum / (n - 1));}// Function to find coefficient of variation.float coefficientOfVariation(float arr[], int n){ return standardDeviation(arr, n) / mean(arr, n);}// Driver Programint main(){ float arr[] = { 15, 36, 53.67, 25.45, 67.8, 56, 78.09 }; int n = sizeof(arr) / sizeof(arr[0]); cout << coefficientOfVariation(arr, n); return 0;} |
Java
//Java Program to find coefficient of // variation of given arrayimport java.io.*;class GFG { // Function to find mean of given array. static double mean(double arr[], int n) { double sum = 0; for (int i = 0; i < n; i++) sum = sum + arr[i]; return sum / n; } // Function to find standard // deviation of given array. static double standardDeviation(double arr[], int n) { double sum = 0; for (int i = 0; i < n; i++) sum = sum + (arr[i] - mean(arr, n)) * (arr[i] - mean(arr, n)); return Math.sqrt(sum / (n - 1)); } // Function to find coefficient of variation. static double coefficientOfVariation(double arr[], int n) { return (standardDeviation(arr, n) / mean(arr, n)); } // Driver Program public static void main (String[] args) { double arr[] = { 15, 36, 53.67, 25.45, 67.8, 56, 78.09 }; int n = arr.length; System.out.println( coefficientOfVariation(arr, n)); }}//This article is contributed by vt_m. |
Python3
# Program to find coefficient # of variation of given array.import math# Function to find mean of# given array.def mean(arr, n): sum = 0 for i in range(0, n): sum = sum + arr[i] return (sum / n) # Function to find standard # deviation of given array.def standardDeviation(arr, n): sum = 0 for i in range(0, n): sum = (sum + (arr[i] - mean(arr, n)) * (arr[i] - mean(arr, n))) return math.sqrt(sum / (n - 1)) # Function to find coefficient# of variation.def coefficientOfVariation(arr, n): return (standardDeviation(arr, n) / mean(arr, n)) # Driver Programarr = [15, 36, 53.67, 25.45, 67.8, 56, 78.09] n = len(arr)print(round(coefficientOfVariation(arr, n), 5))# This code is contributed by Smitha Dinesh Semwal |
C#
//C# Program to find coefficient of // variation of given arrayusing System;class GFG { // Function to find mean of given array. static float mean(double []arr, int n) { double sum = 0; for (int i = 0; i < n; i++) sum = sum + arr[i]; return (float)sum / n; } // Function to find standard // deviation of given array. static float standardDeviation(double []arr, int n) { double sum = 0; for (int i = 0; i < n; i++) sum = sum + (arr[i] - mean(arr, n)) * (arr[i] - mean(arr, n)); return (float)Math.Sqrt(sum / (n - 1)); } // Function to find coefficient of variation. static float coefficientOfVariation(double []arr, int n) { return(float) (standardDeviation(arr, n) / mean(arr, n)); } // Driver Program public static void Main () { double []arr = { 15, 36, 53.67, 25.45, 67.8, 56, 78.09 }; int n = arr.Length; Console.WriteLine( coefficientOfVariation(arr, n)); }}// This code is contributed by vt_m. |
PHP
<?php// Program to find coefficient of // variation of given array.// Function to find mean// of given array.function mean($arr, $n){ $sum = 0; for ($i = 0; $i < $n; $i++) $sum = $sum + $arr[$i]; return $sum /$n;}// Function to find standard // deviation of given array.function standardDeviation($arr, $n){ $sum = 0; for ($i = 0; $i < $n; $i++) $sum = $sum + ($arr[$i] - mean($arr, $n)) * ($arr[$i] - mean($arr, $n)); return sqrt($sum / ($n - 1));}// Function to find coefficient of variation.function coefficientOfVariation($arr, $n){return standardDeviation($arr, $n) / mean($arr, $n);}// Driver Code$arr = array( 15, 36, 53.67, 25.45, 67.8, 56, 78.09 );$n = count($arr);echo coefficientOfVariation($arr, $n);// This code is contributed by vt_m.?> |
Javascript
<script> // JavaScript Program to find coefficient of // variation of given array // Function to find mean of given array. function mean(arr, n) { let sum = 0; for (let i = 0; i < n; i++) sum = sum + arr[i]; return sum / n; } // Function to find standard // deviation of given array. function standardDeviation(arr, n) { let sum = 0; for (let i = 0; i < n; i++) sum = sum + (arr[i] - mean(arr, n)) * (arr[i] - mean(arr, n)); return Math.sqrt(sum / (n - 1)); } // Function to find coefficient of variation. function coefficientOfVariation(arr, n) { return (standardDeviation(arr, n) / mean(arr, n)); } let arr = [ 15, 36, 53.67, 25.45, 67.8, 56, 78.09 ]; let n = arr.length; document.write( coefficientOfVariation(arr, n).toFixed(5)); </script> |
Output
0.48177
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