Given an integer N, the task is to print all the substring of N without doing any conversion i.e converting it into a string or an array.
Examples:
Input: N = 12345
Output: Possible Substrings: {1, 12, 123, 1234, 12345, 2, 23, 234, 2345, 3, 34, 345, 4, 45, 5}
Input: N = 123
Output: Possible Substrings: {1, 12, 123, 2, 23, 3}
Approach:
- Take the power of 10 according to size.
- Divide the number till it will become 0 and print.
- Then change the number to next the position of that number by taking the modulo with k.
- Update the no. of digits.
- Repeat the same process till n becomes 0.
Below is the implementation of above approach:
C++
// C++ implementation of above approach#include <bits/stdc++.h>using namespace std;// Function to print the substrings of a numbervoid printSubstrings(int n){ // Calculate the total number of digits int s = log10(n); // 0.5 has been added because of it will // return double value like 99.556 int d = (int)(pow(10, s) + 0.5); int k = d; while (n) { // Print all the numbers from // starting position while (d) { cout << n / d << endl; d = d / 10; } // Update the no. n = n % k; // Update the no.of digits k = k / 10; d = k; }}// Driver codeint main(){ int n = 123; printSubstrings(n); return 0;} |
Java
// Java implementation // of above approachimport java.util.*;import java.lang.*;import java.io.*;class GFG{// Function to print the// substrings of a numberstatic void printSubstrings(int n){ // Calculate the total // number of digits int s = (int)Math.log10(n); // 0.5 has been added because // of it will return double // value like 99.556 int d = (int)(Math.pow(10, s) + 0.5); int k = d; while (n > 0) { // Print all the numbers // from starting position while (d > 0) { System.out.println(n / d); d = d / 10; } // Update the no. n = n % k; // Update the no.of digits k = k / 10; d = k; }}// Driver codepublic static void main(String args[]){ int n = 123; printSubstrings(n);}}// This code is contributed // by Subhadeep |
Python3
# Python3 implementation of above approachimport math# Function to print the substrings of a numberdef printSubstrings(n): # Calculate the total number of digits s = int(math.log10(n)); # 0.5 has been added because of it will # return double value like 99.556 d = (math.pow(10, s)); k = d; while (n > 0): # Print all the numbers from # starting position while (d > 0): print(int(n // d)); d = int(d / 10); # Update the no. n = int(n % k); # Update the no.of digits k = int(k // 10); d = k;# Driver codeif __name__ == '__main__': n = 123; printSubstrings(n);# This code is contributed by Rajput-Ji |
C#
// C# implementation // of above approachusing System;class GFG{// Function to print the// substrings of a numberstatic void printSubstrings(int n){ // Calculate the total // number of digits int s = (int)Math.Log10(n); // 0.5 has been added because // of it will return double // value like 99.556 int d = (int)(Math.Pow(10, s) + 0.5); int k = d; while (n > 0) { // Print all the numbers // from starting position while (d > 0) { Console.WriteLine(n / d); d = d / 10; } // Update the no. n = n % k; // Update the no.of digits k = k / 10; d = k; }}// Driver codepublic static void Main(){ int n = 123; printSubstrings(n);}}// This code is contributed // by mits |
PHP
<?php// PHP implementation of above approach// Function to print the substrings // of a numberfunction printSubstrings($n){ // Calculate the total number // of digits $s = (int)log10($n); // 0.5 has been added because // of it will return double // value like 99.556 $d = (int)(pow(10, $s) + 0.5); $k = $d; while ($n) { // Print all the numbers from // starting position while ($d) { echo (int)($n / $d) . "\n"; $d = (int)($d / 10); } // Update the no. $n = $n % $k; // Update the no.of digits $k = (int)($k / 10); $d = $k; }}// Driver code$n = 123;printSubstrings($n);// This code is contributed by mits?> |
Javascript
<script>// javascript implementation // of above approach// Function to print the// substrings of a numberfunction printSubstrings(n){ // Calculate the total // number of digits var s = parseInt(Math.log10(n)); // 0.5 has been added because // of it will return double // value like 99.556 var d = parseInt((Math.pow(10, s) + 0.5)); var k = d; while (n > 0) { // Print all the numbers // from starting position while (d > 0) { document.write(parseInt(n / d)+"<br>"); d = parseInt(d / 10); } // Update the no. n = n % k; // Update the no.of digits k = parseInt(k / 10); d = k; }}// Driver codevar n = 123;printSubstrings(n);// This code contributed by Princi Singh </script> |
Output:
1 12 123 2 23 3
Time Complexity: O(nlogn)
Auxiliary Space: O(1)
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