Although Java is strictly passed by value, the precise effect differs between whether a primitive type or a reference type is passed. When we pass a primitive type to a method, it is passed by value. But when we pass an object to a method, the situation changes dramatically, because objects are passed by what is effectively call-by-reference. Java does this interesting thing that’s sort of a hybrid between pass-by-value and pass-by-reference.
Basically, a parameter cannot be changed by the function, but the function can ask the parameter to change itself via calling some method within it.
- While creating a variable of a class type, we only create a reference to an object. Thus, when we pass this reference to a method, the parameter that receives it will refer to the same object as that referred to by the argument.
- This effectively means that objects act as if they are passed to methods by use of call-by-reference.
- Changes to the object inside the method do reflect the object used as an argument.
Illustration: Let us suppose three objects ‘ob1’ , ‘ob2’ and ‘ob3’ are created:
ObjectPassDemo ob1 = new ObjectPassDemo(100, 22); ObjectPassDemo ob2 = new ObjectPassDemo(100, 22); ObjectPassDemo ob3 = new ObjectPassDemo(-1, -1);
From the method side, a reference of type Foo with a name a is declared and it’s initially assigned to null.
boolean equalTo(ObjectPassDemo o);
As we call the method equalTo, the reference ‘o’ will be assigned to the object which is passed as an argument, i.e. ‘o’ will refer to ‘ob2’ as the following statement execute.
System.out.println("ob1 == ob2: " + ob1.equalTo(ob2));
Now as we can see, equalTo method is called on ‘ob1’ , and ‘o’ is referring to ‘ob2’. Since values of ‘a’ and ‘b’ are same for both the references, so if(condition) is true, so boolean true will be return.
if(o.a == a && o.b == b)
Again ‘o’ will reassign to ‘ob3’ as the following statement execute.
System.out.println("ob1 == ob3: " + ob1.equalTo(ob3));
- Now as we can see, the equalTo method is called on ‘ob1’ , and ‘o’ is referring to ‘ob3’. Since values of ‘a’ and ‘b’ are not the same for both the references, so if(condition) is false, so else block will execute, and false will be returned.
In Java we can pass objects to methods as one can perceive from the below program as follows:
Example:
Java
// Java Program to Demonstrate Objects Passing to Methods.// Class// Helper classclass ObjectPassDemo { int a, b; // Constructor ObjectPassDemo(int i, int j) { a = i; b = j; } // Method boolean equalTo(ObjectPassDemo o) { // Returns true if o is equal to the invoking // object notice an object is passed as an // argument to method return (o.a == a && o.b == b); }}// Main classpublic class GFG { // MAin driver method public static void main(String args[]) { // Creating object of above class inside main() ObjectPassDemo ob1 = new ObjectPassDemo(100, 22); ObjectPassDemo ob2 = new ObjectPassDemo(100, 22); ObjectPassDemo ob3 = new ObjectPassDemo(-1, -1); // Checking whether object are equal as custom // values // above passed and printing corresponding boolean // value System.out.println("ob1 == ob2: " + ob1.equalTo(ob2)); System.out.println("ob1 == ob3: " + ob1.equalTo(ob3)); }} |
ob1 == ob2: true ob1 == ob3: false
Defining a constructor that takes an object of its class as a parameter
One of the most common uses of object parameters involves constructors. Frequently, in practice, there is a need to construct a new object so that it is initially the same as some existing object. To do this, either we can use Object.clone() method or define a constructor that takes an object of its class as a parameter.
Example
Java
// Java program to Demonstrate One Object to// Initialize Another// Class 1class Box { double width, height, depth; // Notice this constructor. It takes an // object of type Box. This constructor use // one object to initialize another Box(Box ob) { width = ob.width; height = ob.height; depth = ob.depth; } // constructor used when all dimensions // specified Box(double w, double h, double d) { width = w; height = h; depth = d; } // compute and return volume double volume() { return width * height * depth; }}// MAin classpublic class GFG { // Main driver method public static void main(String args[]) { // Creating a box with all dimensions specified Box mybox = new Box(10, 20, 15); // Creating a copy of mybox Box myclone = new Box(mybox); double vol; // Get volume of mybox vol = mybox.volume(); System.out.println("Volume of mybox is " + vol); // Get volume of myclone vol = myclone.volume(); System.out.println("Volume of myclone is " + vol); }} |
Volume of mybox is 3000.0 Volume of myclone is 3000.0
Returning Objects
In java, a method can return any type of data, including objects. For example, in the following program, the incrByTen( ) method returns an object in which the value of an (an integer variable) is ten greater than it is in the invoking object.
Example
Java
// Java Program to Demonstrate Returning of Objects// Class 1class ObjectReturnDemo { int a; // Constructor ObjectReturnDemo(int i) { a = i; } // Method returns an object ObjectReturnDemo incrByTen() { ObjectReturnDemo temp = new ObjectReturnDemo(a + 10); return temp; }}// Class 2// Main classpublic class GFG { // Main driver method public static void main(String args[]) { // Creating object of class1 inside main() method ObjectReturnDemo ob1 = new ObjectReturnDemo(2); ObjectReturnDemo ob2; ob2 = ob1.incrByTen(); System.out.println("ob1.a: " + ob1.a); System.out.println("ob2.a: " + ob2.a); }} |
ob1.a: 2 ob2.a: 12
Note: When an object reference is passed to a method, the reference itself is passed by use of call-by-value. However, since the value being passed refers to an object, the copy of that value will still refer to the same object that its corresponding argument does. That’s why we said that java is strictly pass-by-value.
This article is contributed by Gaurav Miglani. If you like Lazyroar and would like to contribute, you can also write an article using write.geeksforgeeks.org or mail your article to review-team@geeksforgeeks.org. See your article appearing on the Lazyroar main page and help other Geeks. Please write comments if you find anything incorrect, or you want to share more information about the topic discussed above.
