A Pandigital Number is a number that makes the use of all digits 1 to 9 exactly once. We are given a number, we need to find if there are two numbers whose multiplication is given number and given three numbers together are pandigital.
Examples:
Input : 7254
Output : Yes
39 * 186 = 7254. We can notice that
the three numbers 39, 186 and 7254
together have all digits from 1 to 9.
Input : 6952
Output : Yes
The idea is to consider all pairs that multiply to given number. For every pair, create a string containing three numbers (given number and current pair). We sort the created string and check if sorted string is equal to “123456789”.
C++
// C++ code to check the number// is Pandigital Product or not#include <bits/stdc++.h>using namespace std;// To check the string formed // from multiplicand, multiplier// and product is pandigitalbool isPandigital(string str){ if (str.length() != 9) return false; sort(str.begin(), str.end()); return str=="123456789";}// calculate the multiplicand, // multiplier, and product// eligible for pandigitalbool PandigitalProduct_1_9(int n){ for (int i = 1; i * i <= n; i++) if (n % i == 0 && isPandigital(to_string(n) + to_string(i) + to_string(n / i))) return true; return false;}// Driver Codeint main(){ int n = 6952; if (PandigitalProduct_1_9(n) == true) cout << "yes"; else cout << "no"; return 0;}// This code is contributed by // Manish Shaw(manishshaw1) |
Java
// Java code to check the number// is Pandigital Product or notimport java.io.*;import java.util.*;class GFG { // calculate the multiplicand, multiplier, and product // eligible for pandigital public static boolean PandigitalProduct_1_9(int n) { for (int i = 1; i*i <= n; i++) if (n % i == 0 && isPandigital("" + n + i + n / i)) return true; return false; } // To check the string formed from multiplicand // multiplier and product is pandigital public static boolean isPandigital(String str) { if (str.length() != 9) return false; char ch[] = str.toCharArray(); Arrays.sort(ch); return new String(ch).equals("123456789"); } // Driver function public static void main(String[] args) { int n = 6952; if (PandigitalProduct_1_9(n) == true) System.out.println("yes"); else System.out.println("no"); }} |
Python3
# Python3 code to check the number # is Pandigital Product or not # Calculate the multiplicand,# multiplier, and product # eligible for pandigital def PandigitalProduct_1_9(n): i = 1 while i * i <= n: if ((n % i == 0) and bool(isPandigital(str(n) + str(i) + str(n // i)))): return bool(True) i += 1 return bool(False)# To check the string formed from # multiplicand multiplier and # product is pandigital def isPandigital(Str): if (len(Str) != 9): return bool(False) ch = "".join(sorted(Str)) if (ch == "123456789"): return bool(True) else: return bool(False)# Driver coden = 6952if (bool(PandigitalProduct_1_9(n))): print("yes") else: print("no") # This code is contributed by divyeshrabadiya07 |
C#
// C# code to check the number// is Pandigital Product or not.using System;class GFG { // calculate the multiplicand, // multiplier, and product // eligible for pandigital public static bool PandigitalProduct_1_9(int n) { for (int i = 1; i*i <= n; i++) if (n % i == 0 && isPandigital("" + n + i + n / i)) return true; return false; } // To check the string formed from multiplicand // multiplier and product is pandigital public static bool isPandigital(String str) { if (str.Length != 9) return false; char []ch = str.ToCharArray(); Array.Sort(ch); return new String(ch).Equals("123456789"); } // Driver function public static void Main() { int n = 6952; if (PandigitalProduct_1_9(n) == true) Console.Write("yes"); else Console.Write("no"); }}// This code is contributed by nitin mittal. |
Javascript
// JavaScript code to check the number// is Pandigital Product or not// To check the string formed // from multiplicand, multiplier// and product is pandigitalfunction isPandigital(str){ if (str.length != 9) return false; let ch = Array.from(str); ch.sort(); let s = ch; if(s == "123456789") return true; else return false;}// calculate the multiplicand, // multiplier, and product// eligible for pandigitalfunction PandigitalProduct_1_9(n){ for (let i = 1; i * i <= n; i++) if (n % i == 0 && isPandigital(n.toString() + i.toString() + (n / i).toString())); return true; return false;}// Driver Codelet n = 6952;if (PandigitalProduct_1_9(n) == true) console.log("yes");else console.log("no");// This code is contributed by Nidhi goel |
PHP
<?php// PHP code to check the number// is Pandigital Product or not// To check the string formed // from multiplicand, multiplier// and product is pandigitalfunction isPandigital($str){ if (strlen($str) != 9) return false; $x = str_split($str); sort($x); $x = implode($x); return strcmp($x, "123456789");}// calculate the multiplicand, // multiplier, and product// eligible for pandigitalfunction PandigitalProduct_1_9($n){ for ($i = 1; $i * $i <= $n; $i++) if ($n % $i == 0 && isPandigital(strval($n) . strval($i) . strval((int)($n / $i)))) return true; return false;}// Driver Code$n = 6050;if (PandigitalProduct_1_9($n)) echo "yes";else echo "no";// This code is contributed // by mits?> |
Output
yes
Time Complexity: O(n^1/2)
Auxiliary Space: O(1).
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